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A ball accelerates at 8 cm/s^2 for 3 seconds, starting with velocity 12 cm/s.
• What will be its velocity after the 3 seconds has elapsed?
We know that at t = 0, the velocity is 12 cm / sec. The acceleration is 8 cm / sec^2. Every second the velocity increases by 8 cm /sec. In three seconds the velocity increases by 24 cm /sec. The initial velocity is 12 cm / sec. So 12 cm / sec + 24 = 36 cm /sec
answer/question/discussion:
• Assuming that acceleration is constant, what will be its average velocity during this interval?
Average Velocity = (Vf + Vo) / 2
Average Velocity = (36 cm /sec + 12 cm / sec) / 2
Average Velocity = 24 cm /sec
answer/question/discussion:
• How far will it travel during this interval?
D = v * t (v = average velocity)
D = (24 cm / sec) * (3 sec)
D = 72 cm
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10 minutes
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&#This looks very good. Let me know if you have any questions. &#