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Sketch a vector representing a 10 Newton force which acts vertically downward.
• Position an x-y coordinate plane so that the initial point of your vector is at the origin, and the angle of the vector as measured counterclockwise from the positive x axis is 250 degrees. This will require that you 'rotate' the x-y coordinate plane from its traditional horizontal-vertical orientation.
answer/question/discussion:
• What are the x and y components of the equilibrant of the force?
If the newton force is straight down, the angle would be 270 degrees.
The x and y axes have been rotated as indicated. The force is at 250 degrees relative to this coordinate system.
What therefore are its components?
What therefore are the components of its equilibrant?
answer/question/discussion:
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3 minutes
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