query 26

#$&*

course Mth 272

8/8 12:14am

026.

*********************************************

Question: `qQuery problem 7.3.38 level curves of z = e^(xy), c = 1, 2, 3, 4, 1/2, 1/3, 1/4.

YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY

Your solution:

The z = c level curve of e^(xy) occurs when e^(xy) = c.

We solve e^(xy) = c for y in terms of x. We first take the natural log of both sides:

ln(e^(xy)) = ln(c), or

xy = ln(c). We then divide both sides by x:

y = ln(c) / x.

For c = 1 we get y = ln(1) / x = 0 / x = 0. Thus the c = 1 level curve is the x axis y = 0.

For c = 2 we get y = ln(2) / x = .7 / x, approximately. This curve passes through the points (1,.7) and (-1, -.7), and is asymptotic to both the x and y axes.

For c = 3 we get y = ln(3) / x = 1.1 / x, approximately. This curve passes through the points (1,1.1) and (-1, -1.1), and is asymptotic to both the x and y axes.

For c = 4 we get y = ln(4) / x = 1.39 / x, approximately. This curve passes through the points (1,1.39) and (-1, -1.39), and is asymptotic to both the x and y axes.

For c = 1/2 we get y = ln(1/2) / x = -.7 / x, approximately. This curve passes through the points (-1,.7) and -1, -.7), and is asymptotic to both the x and y axes.

For c = 1/3 we get y = ln(1/3) / x = -1.1 / x, approximately. This curve passes through the points (-1,1.1) and -1, -1.1), and is asymptotic to both the x and y axes.

For c = 1/4 we get y = ln(1/4) / x = -1.39 / x, approximately. This curve passes through the points (-1,1.39) and -1, -1.39), and is asymptotic to both the x and y axes.

The c = 2, 3, 4 level curves form similar hyperbolas in the first and third quadrant which progressively 'bunch up' closer and closer together. Similar behavior is observed for the c = 1/2, 1/3, 1/4 hyperbolas, which occur in the second and fourth quadrants.

confidence rating #$&*:

^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

.............................................

Given Solution:

`a The z = c level curve of e^(xy) occurs when e^(xy) = c.

We solve e^(xy) = c for y in terms of x. We first take the natural log of both sides:

ln(e^(xy)) = ln(c), or

xy = ln(c). We then divide both sides by x:

y = ln(c) / x.

For c = 1 we get y = ln(1) / x = 0 / x = 0. Thus the c = 1 level curve is the x axis y = 0.

For c = 2 we get y = ln(2) / x = .7 / x, approximately. This curve passes through the points (1,.7) and (-1, -.7), and is asymptotic to both the x and y axes.

For c = 3 we get y = ln(3) / x = 1.1 / x, approximately. This curve passes through the points (1,1.1) and (-1, -1.1), and is asymptotic to both the x and y axes.

For c = 4 we get y = ln(4) / x = 1.39 / x, approximately. This curve passes through the points (1,1.39) and (-1, -1.39), and is asymptotic to both the x and y axes.

For c = 1/2 we get y = ln(1/2) / x = -.7 / x, approximately. This curve passes through the points (-1,.7) and -1, -.7), and is asymptotic to both the x and y axes.

For c = 1/3 we get y = ln(1/3) / x = -1.1 / x, approximately. This curve passes through the points (-1,1.1) and -1, -1.1), and is asymptotic to both the x and y axes.

For c = 1/4 we get y = ln(1/4) / x = -1.39 / x, approximately. This curve passes through the points (-1,1.39) and -1, -1.39), and is asymptotic to both the x and y axes.

The c = 2, 3, 4 level curves form similar hyperbolas in the first and third quadrant which progressively 'bunch up' closer and closer together. Similar behavior is observed for the c = 1/2, 1/3, 1/4 hyperbolas, which occur in the second and fourth quadrants.

STUDENT COMMENT

I had a little bit of trouble applying my graphing here given dimension, but clear pertaining to concept, making a bit more progress.

INSTRUCTOR RESPONSE

You should be very familiar with the graph of y = 1 / x. Focus on the point (1, 1) and the fact that the graph in the right half-plane has asymptotes with the positive y and positive x axes.

If you multiply this function by ln(c) the point becomes (1, ln(c)). For c = 1, 2, 3, 4 the points rise higher and higher, but with less space between successive points. The level curves pass through these points, still with asymptotes at the x and y axes. Each curve is a bit 'higher' than the preceding.

&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&

Self-critique (if necessary):

------------------------------------------------

Self-critique Rating:

*********************************************

Question: `qQuery problem 7.3.46 queuing model W(x,y) = 1 / (x-y), y < x (y = ave arrival rate, x = aver service rate).

What are the values of W at (15, 10), (12, 9), (12, 6) and (4,2)?

YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY

Your solution:

1/5, 1/3, 1/6, 1/2

confidence rating #$&*:

^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

.............................................

Given Solution:

`a 1/5, 1/3, 1/6, 1/2

&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&

Self-critique (if necessary):

------------------------------------------------

Self-critique Rating:

*********************************************

Question: `qYou may take extra time with the following: What is the nature of the worst combination of x and y, and why is this bad--both in terms of the behavior of the function and in terms of the real-world situation?

YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY

Your solution:

x=service, y=arrival rate

therefore the worst senerio would be when the arrival rate was almost as long as the service rate...its worse to have a customer waiting a long time than having a customer being served for a long time

confidence rating #$&*:

^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

.............................................

Given Solution:

`aGood answer by student:

x=service, y=arrival rate

therefore the worst senerio would be when the arrival rate was almost as long as the service rate...its worse to have a customer waiting a long time than having a customer being served for a long time

&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&

Self-critique (if necessary):

------------------------------------------------

Self-critique Rating:

*********************************************

Question: `qQuery Add comments on any surprises or insights you experienced as a result of this assignment."

Self-critique (if necessary):

------------------------------------------------

Self-critique rating:

*********************************************

Question: `qQuery Add comments on any surprises or insights you experienced as a result of this assignment."

Self-critique (if necessary):

------------------------------------------------

Self-critique rating:

#*&!