query 4

course Phy 202

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|??~????????????assignment #004

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004.

Physics II

03-26-2007

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22:40:34

Query introductory set #1, 10-17

Explain how to find the potential difference in volts between two given points on the x axis, due to a given charge at the origin.

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RESPONSE -->

to find the potential difference, just subtract the first value from the second.

confidence assessment: 2

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22:42:26

** Potential difference is the work per Coulomb of charge moved between the two points. To find this work you can multiply the average force on a Coulomb of charge by the displacement from the first point to the second.

You can find an approximate average force by finding the force on a 1 Coulomb test charge at the two points and averaging the two forces. Multiplying this ave force by the displacement gives an approximate potential difference.

Since the force is not a linear function of distance from the given charge, if the ratio of the two distances from the test charge is not small the approximation won't be particularly good. The approximation can be improved to any desired level of accuracy by partitioning the displacement between charges into smaller intervals of displacement and calculating the work done over each. The total work required is found by adding up the contributions from all the subintervals.

University Physics students should understand how this process yields the exact w ""ork, which is the integral of the force function F(x) = k Q / x^2 between the two x values, yielding total work W = k * Q * 1 Coulomb ( 1 / x1 - 1 / x2) and potential difference V = k * Q ( 1 / x1 - 1 / x2). **

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RESPONSE -->

ok the work/C between two points is the potential difference. multiply average force by displacement to get work.

self critique assessment: 2

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22:45:45

Explain how to find the potential difference between two points given the magnitude and direction of the uniform electric field between those points.

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RESPONSE -->

work per C= electric field*`ds

confidence assessment: 2

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22:47:04

** The work per Coulomb done between the two points is equal to the product of the electric field E and the displacement `dr. Thus for constant field E we have V = E * `dr. **

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RESPONSE -->

ok

self critique assessment: 3

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22:48:03

Explain how to find the average electric field between two points given a specific charge and the work done on the charge by the electric field as the charge moves between the points.

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RESPONSE -->

average force=`dw/`ds

average e-field=Fave/q

confidence assessment: 3

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22:48:38

** You get ave force from work and distance: F_ave = `dW / `ds.

You get ave electric field from work and charge: E_ave = F / q.

An alternative:

Find potential difference `dV = `dW / q.

Ave electric field is Eave = `dV / `ds **

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RESPONSE -->

ok

self critique assessment: 3.................................................

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22:50:07

In your own words explain the meaning of voltage.

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RESPONSE -->

voltage is the Newtons of force per test unit Coulomb of charge that is exerted by a certain charge.

confidence assessment: 2

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22:50:26

** Voltage is the work done per unit of charge in moving charge from one point to another. **

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RESPONSE -->

the work done per unit of charge in moving charge from one point to another

self critique assessment: 2

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"

Be very sure you understand these units and concepts. Let me know if you have questions.