course Phy 201
If the velocity of the object changes from 4 cm / sec to 16 cm / sec in 8 seconds, then at what average rate is the velocity changing?* The average rate the velocity is changing, or the acceleration is : 12cm/s divided by 8s = 1.5cm/s^2.
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A ball rolling from rest down a constant incline requires 8.2 seconds to roll the 97 centimeter length of the incline.
• What is its average velocity?
* The average velocity is 97 cm/8.2s = 11.83 cm/s=Vave
An object which accelerates uniformly from rest will attain a final velocity which is double its average velocity.
• What therefore is the final velocity of this ball?
* The final velocity is 2(Vave)=2(11.83cm/s)=23.66 cm/s
• What average rate is the velocity of the ball therefore changing?
* The average rate the velocity is changing, or the acceleration is: the final velocity 23.66cm/s divided by the time interval 8.2 seconds = 2.89 cm/s^2.
An automobile accelerates uniformly down a constant incline, starting from rest. It requires 10 seconds to cover a distance of 132 meters. At what average rate is the velocity of the automobile therefore changing?
* First the average velocity must be found: 132 m/10s = 13.2 m/s. This is then doubled to find the final velocity to be 26.4 m/s. The final velocity is then divided by the time interval of 10s and the average acceleration is found to be 2.64 m/s/s.
Don't think in terms of dividing final vel by time interval; think in terms of dividing change in vel by time interval.
Good work. see my note and let me know if you have questions.
course Phy 201
If the velocity of the object changes from 4 cm / sec to 16 cm / sec in 8 seconds, then at what average rate is the velocity changing?* The average rate the velocity is changing, or the acceleration is : 12cm/s divided by 8s = 1.5cm/s^2.
Your work has been received. Please scroll through the document to see any inserted notes (inserted at the appropriate place in the document, in boldface) and a note at the end. The note at the end of the file will confirm that the file has been reviewed; be sure to read that note. If there is no note at the end, notify the instructor through the Submit Work form, and include the date of the posting to your access page.
A ball rolling from rest down a constant incline requires 8.2 seconds to roll the 97 centimeter length of the incline.
• What is its average velocity?
* The average velocity is 97 cm/8.2s = 11.83 cm/s=Vave
An object which accelerates uniformly from rest will attain a final velocity which is double its average velocity.
• What therefore is the final velocity of this ball?
* The final velocity is 2(Vave)=2(11.83cm/s)=23.66 cm/s
• What average rate is the velocity of the ball therefore changing?
* The average rate the velocity is changing, or the acceleration is: the final velocity 23.66cm/s divided by the time interval 8.2 seconds = 2.89 cm/s^2.
An automobile accelerates uniformly down a constant incline, starting from rest. It requires 10 seconds to cover a distance of 132 meters. At what average rate is the velocity of the automobile therefore changing?
* First the average velocity must be found: 132 m/10s = 13.2 m/s. This is then doubled to find the final velocity to be 26.4 m/s. The final velocity is then divided by the time interval of 10s and the average acceleration is found to be 2.64 m/s/s.
Don't think in terms of dividing final vel by time interval; think in terms of dividing change in vel by time interval.
Good work. see my note and let me know if you have questions.