asst 4 query

course Phy 201

?????~???]??????assignment #004?>???????y????Physics I

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07-26-2006

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17:59:28

Intro Prob 6 given init vel, accel, `dt find final vel, dist

If initial velocity is v0, acceleration is a and time interval is `dt, then in symbols what are the final velocity vf and the displacement `ds?

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RESPONSE -->

vf=v0 +2(vAve), `ds=vAve * `dt

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18:00:19

**You would use accel. and `dt to find `dv:

a * `dt = `dv. Adding `dv to initial vel. vo you get final vel.

Then average initial vel. and final vel. to get ave. vel.:

(v0 + vf) / 2 = ave. vel.

You would then multiply ave. vel. and `dt together to get the distance.

For example if a = 3 m/s^2, `dt = 5 s and v0 = 3 m/s:

3 m/s^2 * 5 s = 15 m/s = `dv

15 m/s + 3 m/s = 18 m/s = fin. vel.

(18 m/s + 3 m/s) / 2 = 10.5 m/s = vAve

10.5 m/s * 5 s = 52.5 m = dist.

In more abbreviated form:

a * `dt = `dv

v0 + `dv = vf

(vf + v0) /2 = vAve

vAve * `dt = `ds so

`ds = (vf + v0) / 2 * `dt.

**

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RESPONSE -->

ok i found my vAve before my `dv and this could make a difference if it's not uniformly accelerating.

Good observation.

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18:01:17

What is the displacement `ds associated with uniform acceleration from velocity v0 to velocity vf in clock time `dt?

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RESPONSE -->

`ds=`dv *`dt

`dv=vf-v0

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18:01:37

** Since accel is uniform vAve = (v0 + vf) / 2.

Thus displacement is

`ds = vAve * `dt = (v0 + vf) / 2 * `dt,

which is the first equation of uniformly accelerated motion. **

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RESPONSE -->

ok. i used change in v not vAve, which is wrong.

Right. Something can move a long way without changing its velocity.

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18:03:15

Describe the flow diagram we obtain for the situation in which we know v0, vf and `dt.

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RESPONSE -->

v0 and vf can find both vAve and `dv. `dv is the used with `dt to find the a. vAve and `dt can be combined to find `ds.

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18:03:34

** The first level in the diagram would contain `dt, v0 and vf.

Then v0 and vf would connect to `dv in the second level.

The second level would also contain vAve, connected from vf in the first level to v0 in the first level.

The third level would contain an a, connected to `dv in the second level and `dt in the first level.

The third level would also contain `ds, connected to vAve in the fourth level and `dt in the first level. **

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RESPONSE -->

ok

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18:03:45

Query Add any surprises or insights you experienced as a result of this assignment.

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RESPONSE -->

n/a

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18:04:01

** Student Response: I think I really confused what information stood for what in the Force and Pendulum Experiment. However, I enjoy doing the flow diagrams. They make you think in a different way than you are used to. INSTRUCTOR NOTE: These diagrams are valuable for most people. Not all--it depends on learning style--but most. **

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RESPONSE -->

k

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Your work on this assignment is good. See my notes and let me know if you have questions.