Phy 231
Your 'cq_1_02.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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A graph is constructed representing velocity vs. clock time for the interval between clock times t = 5 seconds and t = 13 seconds. The graph consists of a straight
line from the point (5 sec, 16 cm/s) to the point (13 sec, 40 cm/s).
What is the clock time at the midpoint of this interval?
answer/question/discussion: 9 sec
This answer was determined by adding both x-coordinates (5 s and 13 s) and then dividing by two.
What is the velocity at the midpoint of this interval?
answer/question/discussion: 28 cm/s
This answer was determined the same way as the above answer; I added the two y-coor together (40 cm/s and 16 cm/s) and divided by 2.
How far do you think the object travels during this interval?
answer/question/discussion: 192 cm
This answer was obtained by subtracting 40 cm/s from 16 cm/s, which equals 24 cm/s. I then did the same thing with the time interval, subtracting 13 s from 5s,
which equals 8 s. Then, I multiplied 24 cm/s by 8 s to get 192 cm.
By how much does the clock time change during this interval?
answer/question/discussion: 8 s
This answer was obtained by subtracting 5 s from 13 s, which equals 8 s.
By how much does velocity change during this interval?
answer/question/discussion: 24 cm/s
This answer was obtained by subtracting 16 cm/s from 40 cm/s.
What is the average rate of change of velocity with respect to clock time on this interval?
answer/question/discussion: 28 cm/s
This was obtained by adding 40 cm/s and 16 cm/s and then dividing by 2.
What is the rise of the graph between these points?
answer/question/discussion: 24 cm/s
This was obtained by subtracting 16 cm/s from 40 cm/s.
What is the run of the graph between these points?
answer/question/discussion: 8 s
This was obtained by subtracting 5 s from 13 s.
What is the slope of the graph between these points?
answer/question/discussion: 3
This was obtained by using the rise / run formula, which is 24 / 8.
What does the slope of the graph tell you about the motion of the object during this interval?
answer/question/discussion: The graph shows that the object is gaining positive speed over the time interval.
What is the average rate of change of the object's velocity with respect to clock time during this interval?
answer/question/discussion: 12 cm/s
This answer was obtained by subtracting 16 cm/s from 40 cm/s and then dividing by 2.
Not sure about this one - I'm unsure how this differs from the earlier question, so I made a reasonable guess. If I'm wrong, can you please explain this for me?
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20 minutes
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You're reasoning well, but you're making some errors in the details of some of your solutions. You'll see what I mean in the link below:
&#At least part of your solution does not agree with the solution and comments given at the link below. You should view the solution at that link and self-critique as indicated there.
Solution
This link also expands on these topics and alerts you to many of the common errors made by students in the first part of this course. &#