Phy 231
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A ball accelerates at 8 cm/s^2 for 3 seconds, starting with velocity 12 cm/s.
What will be its velocity after the 3 seconds has elapsed?
answer/question/discussion: 36 cm/s
If the ball is accelerating at 8 cm/s/s, then it's velocity will increase by 8 cm/s every second. Therefore, over the span of 3 seconds, the velocity will have increased by 8 cm/s^2 * 3 s = 24 cm/s. Adding this total to the original velocity of 12 cm/s, we get 36 cm/s.
Assuming that acceleration is constant, what will be its average velocity during this interval?
answer/question/discussion: 24 cm/s
If final velocity = 36 cm/s and initial velocity = 12 cm/s. Then vAve = (36 cm/s + 12 cm/s) / 2 = 24 cm/s.
How far will it travel during this interval?
answer/question/discussion: 72 cm
If the vAve during the time interval is 24 cm/s, then the ball will travel 24 cm/s * 3 s = 72 cm.
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10 minutes
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&#Very good work. Let me know if you have questions. &#