course Phy 231
An airplane on a runway has velocity 5 m/s at clock time t = 10 sec, when it is 89 meters from a certain roadkill, and velocity 8.6 m/s at clock time t = 16 sec. Between these two clock times it accelerates uniformly at .6 m/s/s. Find its velocity at the end of the time interval and its average velocity during this time interval. How far from the roadkill is the airplane at clock time t = 16 sec?ANSWER:
The velocity at the end of the clock time is stated in the question as 8.6 m/s. The average velocity during the time interval = 6.8 m/s
vAve = (vf + v0) / 2 = (5 m/s + 8.6 m/s) / 2 = 6.8 m/s
During the time interval, the airplane travelled 40.8 m
6.8 m/s * 6 s = 40.8 m
At t = 10, the airplane was 89 m from the roadkill. At t = 16, the airplane was 89 m - 40.8 m = 48.2 m away from the roadkill.
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