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phy 121
Your 'cq_1_06.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_06.1_labelMessages **
For each situation state which of the five quantities v0, vf, `ds, `dt and a are given, and give the value of each.
A ball accelerates uniformly from 10 cm/s to 20 cm/s while traveling 45 cm.
answer/question/discussion: ->->->->->->->->->->->-> :
V0 = 10cm/s
Vf = 20cm/s
'ds = 45cm
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A ball accelerates uniformly at 10 cm/s^2 for 3 seconds, and at the end of this interval is moving at 50 cm/s.
answer/question/discussion: ->->->->->->->->->->->-> :
a = 10cm/s^2
'dt = 3 sec
vf = 50cm/s
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A ball travels 30 cm along an incline, starting from rest, while accelerating at 20 cm/s^2.
answer/question/discussion: ->->->->->->->->->->->-> :
'ds = 30 cm
v0 = 0cm/s
a = 20 cm/s^2
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Then for each situation answer the following:
Is it possible from this information to directly determine vAve?
answer/question/discussion: ->->->->->->->->->->->-> :
Yes, in Q1 Vave is (Vf+V0) /2
No not directly
In Q3, Vave can be found by using the fourth equation: vf^2 = v0^2 + 2 a `ds. once we have Vf we can solve for Vave
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Is it possible to directly determine `dv?
answer/question/discussion: ->->->->->->->->->->->-> :
Yes, 'dv = Vf - V0
Yes, a = 'dv / 'dt, so we can solve for 'dv by 'dv = a * 'dt
Yes, using `ds = v0 `dt + .5 a `dt^2 we solve for 'dt. Once 'dt is know, we can take a * 'dt to give 'dv
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*#&!
&#Good responses. Let me know if you have questions. &#