PHY 121
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A ball falls freely from rest at a height of 2 meters. Observations indicate that the ball reaches the ground in .64 seconds.
• Based on this information what is its acceleration?
answer/question/discussion: ->->->->->->->->->->->-> :
Well if the ball fell from a rest position then the initial velocity would 0 m/s. Therefore 2 m / .64 s = 3.13 m/s which is final velocity. So 3.13 m/s is also ‘dv. That means that aAve = 3.13 m/s / .64 s = 4.89 m/s^2.
• Is this consistent with an observation which concludes that a ball dropped from a height of 5 meters reaches the ground in 1.05 seconds?
answer/question/discussion: ->->->->->->->->->->->-> :
vf = 5 m / 1.05 s = 4.76 m/s
aAve = 4.76 m/s / 1.05 s = 4.53 m/s^2
So I would have to say no.
• Are these observations consistent with the accepted value of the acceleration of gravity, which is 9.8 m / s^2?
answer/question/discussion: ->->->->->->->->->->->-> :
I am not quite sure how to go about determine this.
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20 minutes
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you used vAve instead of `dv to find accelerations. Be sure you understand; check the link.
&#Please compare your solutions with the expanded discussion at the link
Solution
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