Assignment 1

course Mth 158

Your work has been received. Please scroll through the document to see any inserted notes (inserted at the appropriate place in the document, in boldface) and a note at the end. The note at the end of the file will confirm that the file has been reviewed; be sure to read that note. If there is no note at the end, notify the instructor through the Submit Work form, and include the date of the posting to your access page.

16:49:58 query R.1.14 (was R.1.6) Of the numbers in the set {-sqrt(2), pi + sqrt(2), 1 / 2 + 10.3} which are counting numbers, which are rational numbers, which are irrational numbers and which are real numbers?

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RESPONSE --> None of the numbers are counting numbers. 1/2 + 10.3 are rational numbers. -sqrt2, pi + sqrt2 are irrational numbers All numbers given are real numbers.

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16:50:14 ** Counting numbers are the numbers 1, 2, 3, .... . None of the given numbers are counting numbers Rational numbers are numbers which can be expressed as the ratio of two integers. 1/2+10.3 are rational numbers. Irrational numbers are numbers which can be expressed as the ratio of two integers. {-sqrt(2)}, pi+sqrt(2) are irrational numbers.. **

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RESPONSE --> ok

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16:51:34 query R.1.32 (was R.1.24) Write in symbols: The product of 2 and x is the product of 4 and 6

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RESPONSE --> 2*x = 4*6

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16:51:40 ** The product of 2 and x is 2 * x and the product of 4 and 6 iw 4 * 6. To say that these are identical is to say that 2*x=4*6. **

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RESPONSE --> ok

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16:54:47 query R.1.50 (was R.1.42) Explain how you evaluate the expression 2 - 5 * 4 - [ 6 * ( 3 - 4) ]

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RESPONSE --> 2 - 5 * 4 - [ 6 * ( 3 - 4) ] first evaluate the () 2 - 5 * 4 - [ 6 * -1 ] then evaluate the [] 2 - 5 * 4 - (-6) then multiply 5 and 4 2-20+6 then add and subtract 2-20+6 = -12

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16:54:53 **Starting with 2-5*4-[6*(3-4)]. First you evaluate the innermost group to get 2-5*4-[6*-1] . Then multiply inside brackets to get 2-5*4+6. Then do the multiplication to get 2-20+6. Then add and subtract in order, obtaining -12. **

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RESPONSE --> ok

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16:57:46 query R.1.80 (was R.1.72) Explain how you use the distributive property to remove the parentheses from the express (x-2)(x-4).

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RESPONSE --> (x-2)(x-4) x(x-4) - 2(x-4) x^2 - 4x - 2x + 8 add like terms x^2 - 6x + 8

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16:57:55 ** COMMON ERROR: Using FOIL. FOIL is not the Distributive Law. FOIL works for binomial expressions. FOIL follows from the distributive law but is of extremely limited usefulness and the instructor does not recommend relying on FOIL. Starting with (x-2)(x-4) ; one application of the Distributive Property gives you x(x-4) - 2(x-4) . Applying the property to both of the other terms we get x^2 - 4x - (2x -8). Simplifying: x^2 - 4x - 2x + 8 or x^2 - 6x + 8. *

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RESPONSE --> ok

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17:00:27 query R.1.86 (was R.1.78) Explain why (4+3) / (2+5) is not equal to 4/2 + 3/5.

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RESPONSE --> Starting with: (4+3) / (2+5) = do work in () first 7/7 = 1 4/2 + 3/5 = 2 + 3/5 = 2 3/5 therefore 1 is not equal to 2 3/5

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17:00:37 ** Good answer but at an even more fundamental level it comes down to order of operations. (4+3)/(2+5) means 7/7 which is equal to 1. By order of operations, in which multiplications and divisions precede additions and subtractions, 4/2+3/5 means (4/2) + (3/5), which gives us 2+3/5 = 2 3/5 **

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RESPONSE --> ok

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17:00:54 Query Add comments on any surprises or insights you experienced as a result of this assignment.

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RESPONSE --> no comments

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17:01:01

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RESPONSE --> ok

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Your work looks good. Let me know if you have questions.