Assignment 3

Your work has been received. Please scroll through the document to see any inserted notes (inserted at the appropriate place in the document, in boldface) and a note at the end. The note at the end of the file will confirm that the file has been reviewed; be sure to read that note. If there is no note at the end, notify the instructor through the Submit Work form, and include the date of the posting to your access page.

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RESPONSE --> a^2 + b^2 = c^2 14^2 + 48^2 = c^2 196 + 2304 = c^2 2500 = c^2 50 = c

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14:12:42 ** The Pythagorean Theorem tells us that c^2 = a^2 + b^2, where a and b are the legs and c the hypotenuse. Substituting 14 and 48 for a and b we get c^2 = 14^2 + 48^2, so that c^2 = 196 + 2304 or c^2 = 2500. This tells us that c = + sqrt(2500) or -sqrt(2500). Since the length of a side can't be negative we conclude that c = +sqrt(2500) = 50. **

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RESPONSE --> ok

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14:14:05 query R.3.18 (was R.3.12). Is a triangle with legs of 10, 24 and 26 a right triangle, and how did you arrive at your answer?

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RESPONSE --> 10^2 = 100 24^2 = 576 26^2 = 676 100+576=676 676 = 676 yes this is a right triangle

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14:14:15 ** Using the Pythagorean Theorem we have c^2 = a^2 + b^2, if and only if the triangle is a right triangle. Substituting we get 26^2 = 10^2 + 24^2, or 676 = 100 + 576 so that 676 = 676 This confirms that the Pythagorean Theorem applies and we have a right triangle. **

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RESPONSE --> ok

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14:19:44 query R.3.30 (was R.3.24). What are the volume and surface area of a sphere with radius 3 meters, and how did you obtain your result?

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RESPONSE --> V=4/3 pi r^3 V = 4/3 pi 3^3 V= 4/3 pi 27 V = 113.097 m^3 S=4 pi r^2 S=4 pi 3^2 S=4 pi 9 S= 113.097m^2

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14:19:50 ** To find the volume and surface are a sphere we use the given formulas: Volume = 4/3 * pi * r^3 V = 4/3 * pi * 3^3 V = 4/3 * pi * 27 V = 36pi m^3 Surface Area = 4 * pi * r^2 S = 4 * pi * 3^2 S = 4 * pi * 9 S = 36pi m^2. **

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RESPONSE --> ok

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14:26:24 query R.3.42 (was R.3.36). A pool of radius 10 ft is enclosed by a deck of width 3 feet. What is the area of the deck and how did you obtain this result?

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RESPONSE --> The pool area is: A=pi 10^2 = 314.159 ft^2 The radius of the deck is 10 + 3 = 13 ft The area of the deck plus the pool is: A=pi 13^2 = 530.929 ft^2 530.929 ft^2 - 314.159 ft^2 = 216.77 ft^2 The area of the deck is 216.77 ft^2

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14:26:31 ** The deck plus the pool gives you a circle of radius 10 ft + 3 ft = 13 ft. The area of the deck plus the pool is therefore pi * (13 ft)^2 = 169 pi ft^2. So the area of the deck must be deck area = area of deck and pool - area of pool = 169 pi ft^2 - 100 pi ft^2 = 69 pi ft^2. **

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RESPONSE --> ok

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You did very well on thsi query. Let me know if you have questions.