Phy 201
Your 'cq_1_02.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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The problem:
A graph is constructed representing velocity vs. clock time for the interval between clock times t = 5 seconds and t = 13 seconds. The graph consists of a straight line from the point (5 sec, 16 cm/s) to the point (13 sec, 40 cm/s).
What is the clock time at the midpoint of this interval?
answer/question/discussion: 9 seconds
What is the velocity at the midpoint of this interval?
answer/question/discussion: 28 cm/s
How far do you think the object travels during this interval?
answer/question/discussion: 252 cm. I calculated this by adding up all the velocities in this time interval. I do not feel this is really how you are suppose to go about finding how far the object traveled, when looking at the graph I made this could be a logical answer.
By how much does the clock time change during this interval?
answer/question/discussion: 8 seconds
By how much does velocity change during this interval?
answer/question/discussion: 24 cm/s
What is the average rate of change of velocity with respect to clock time on this interval?
answer/question/discussion: average rate of change in velocity = (40-16 = 24 cm/s) 24 / 8 = 3 cm/s
What is the rise of the graph between these points?
answer/question/discussion: 8
What is the run of the graph between these points?
answer/question/discussion: 24
What is the slope of the graph between these points?
answer/question/discussion: slope= rise/run = 1/3
What does the slope of the graph tell you about the motion of the object during this interval?
answer/question/discussion: The slope tells you that the line runs 3 times as long as the line rises.
What is the average rate of change of the object's velocity with respect to clock time during this interval?
answer/question/discussion: average rate of change in velocity = (40-16 = 24 cm/s) 24 / 8 = 3 cm/s
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20 minutes
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Good answers on most questions, but you have a units error and another answer that is numerically incorrect.
&#At least part of your solution does not agree with the solution and comments given at the link below. You should view the solution at that link and self-critique as indicated there.
Solution
This link also expands on these topics and alerts you to many of the common errors made by students in the first part of this course. &#