course Mth 173
What is the antiderivative of .001t^2 + .14t + 1.8?If I look back at your notes of the antiderivative of a linear function is says that if y' = mt + b then y = .5 m t^2 + b t + c
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so that makes me think that the if v(t) = .001t^2 + .14t + 1.8 then = .001t + .14
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You are correct that the antiderivative of a linear function is says that if y' = mt + b then y = .5 m t^2 + b t + c .
However this does not mean that the antiderivative of y = . 5 m t^2 + b t + c is m t + b.
If function f ' (x) is the derivative of the function f(x), then the function f(x) is an antiderivative of the function f ' (x).
Hint: What is the derivative of x^3?
What is the derivative of 5 x^3?
What is the derivative of x^3 / 12?
If the derivative of an unknown function is x^2, then what is the function?
That function would be an antiderivative of x^2.
What would be an antiderivative of .0723 x^3?
Submit a copy of this document and include your best answers to these questions. If it then becomes clear how to find an antiderivative of .001t^2 + .14t + 1.8, go ahead and give me your reasoning on this question also.