Phy 201
Your 'cq_1_05.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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The problem:
A ball accelerates at 8 cm/s^2 for 3 seconds, starting with velocity 12 cm/s.
• What will be its velocity after the 3 seconds has elapsed?
answer/question/discussion: 12 cm/s + (8 cm/s^2 * 3 s) = 36 cm/s^2
• Assuming that acceleration is constant, what will be its average velocity during this interval?
answer/question/discussion: (v0 + vf) / 2 = (12 cm/s + 36 cm/s^2) /2 = 24 cm/s^2
• How far will it travel during this interval?
answer/question/discussion: 12 cm + 36 cm = 48 cm.
12 cm and 36 cm are not quantities related to this problem.
12 cm/s and 36 cm/s are quantities related to this problem.
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10 minutes
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&#At least part of your solution does not agree with the solution and comments given at the link below. You should view the solution at that link and self-critique as indicated there.
Solution
This link also expands on these topics and alerts you to many of the common errors made by students in the first part of this course. &#