Phy 201
Your 'cq_1_7.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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Seed 7.1
A ball falls freely from rest at a height of 2 meters. Observations indicate that the ball reaches the ground in .64 seconds.
• Based on this information what is its acceleration?
answer/question/discussion: aAVE = `dv / `dt
.64- 0 / 2-0 = .32 m/sec
.64 s is a time interval, not a velocity
• Is this consistent with an observation which concludes that a ball dropped from a height of 5 meters reaches the ground in 1.05 seconds?
answer/question/discussion: No, because 1.05 - 0 / 5-0 = .21 m/sec and to be consistent wouldn’t they have to be accelerating at the same rate??
• Are these observations consistent with the accepted value of the acceleration of gravity, which is 9.8 m / s^2?
answer/question/discussion: I would not think so because if it takes an object 1.05 seconds to reach the ground when being dropped from 5 meters I don’t see how this correlates to the accepted acceleration of gravity.
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15 minutes
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You aren't calculating the accelerations correctly.
&#At least part of your solution does not agree with the solution and comments given at the link below. You should view the solution at that link and self-critique as indicated there.
Solution
This link also expands on these topics and alerts you to many of the common errors made by students in the first part of this course. &#