Your 'cq_1_10.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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A pendulum requires 2 seconds to complete a cycle, which consists of a complete back-and-forth oscillation (extreme point to equilibrium to opposite extreme point back to equilibrium and finally to the original extreme point). As long as the amplitude of the motion (the amplitude is the distance from the equilibrium position to the extreme point) is small compared to the length of the pendulum, the time required for a cycle is independent of the amplitude.
• How long does it take to get from one extreme point to the other, how long from an extreme point to equilibrium, and how long to go from extreme point to equilibrium to opposite extreme point and back to equilibrium?
answer/question/discussion: From one extreme point to the other it would take 1 sec. From one extreme point to equillibrium would be .5 sec and from extreme point to equilibrium to opposite to equilibrium back to the extreme point it will take 2 sec.
• What reasonable assumption did you make to arrive at your answers?
answer/question/discussion: An entire cycle lasts 2 sec. That is from one extreme point past equilibrium to the other extreme point back to equilibrium and to that same extreme point. From one extreme point to the other is equivalent to half of a cycle so that would have to equal 1 sec. Then, from extreme point to equilibrium is ¼ of a cycle so it equals .5 sec.
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5 minutes
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0,-2
-.45,.63
-.32,.45
.16,.47
.52,1.5
For the each of the 5 vectors I used sin and cos functions to find x and y components by x= Fcostheta, y= Fsintheta; with the Force being estimated in a earlier from a scale of 4cm/N
x comp = -.09
y comp = 1.05
These results are different when you include the sin and cos of each angle. I think my angles may have caused some discrep. in my results however these numbers appear to be quite different than my alternative components. I do believe this method is better.
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-.57,.57
.55,1.6
0,-2
x = -.02
y = .17
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3.5-4 hrs
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I am not certain I provide the correct methods where stated. I got confused while doing this lab but I understand the concepts and how to find vectors, magnitude etc. I kept my data organized on my grid however my estimates dont add up for the different components
0,-2
-.45,.63
-.32,.45
.16,.47
.52,1.5
For the each of the 5 vectors I used sin and cos functions to find x and y components by x= Fcostheta, y= Fsintheta; with the Force being estimated in a earlier from a scale of 4cm/N
x comp = -.09
y comp = 1.05
These results are different when you include the sin and cos of each angle. I think my angles may have caused some discrep. in my results however these numbers appear to be quite different than my alternative components. I do believe this method is better.
** **
-.57,.57
.55,1.6
0,-2
x = -.02
y = .17
** **
** **
3.5-4 hrs
** **
I am not certain I provide the correct methods where stated. I got confused while doing this lab but I understand the concepts and how to find vectors, magnitude etc. I kept my data organized on my grid however my estimates dont add up for the different components
The cq problem looks good.
It appears that your responses to the Force Vectors experiment were appended in this submission. Can you copy and paste your responses to that experiment into the form for the Force Vectors experiment and resubmit it? If the responses are submitted in that manner, the program I am using will reassemble them into a complete document which I can then comment on and post.