#$&*
Phy 201
Your 'cq_1_07.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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A ball falls freely from rest at a height of 2 meters. Observations indicate that the ball reaches the ground in .64 seconds.
• Based on this information what is its acceleration?
answer/question/discussion: ->->->->->->->->->->->-> :
2 m / .64 s = 3.125 m/s
v0 = 0 m/s, vf = 3.125 m/s
3.125 m/s - 0 m/s / .64 s = 4.88 m/s^s
@& Acceleration is not ave vel / time interval.
Go back to the rate definition of acceleration and see if you can correctx this.*@
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• Is this consistent with an observation which concludes that a ball dropped from a height of 5 meters reaches the ground in 1.05 seconds?
answer/question/discussion: ->->->->->->->->->->->-> :
5 m / 1.05 s = 4.76 m/s
v0 = 0, vf = 4.76 m/s
4.76 m/s - 0 m/s / 1.05 s = 4.53 m/s^2; the accelerations are very close but they don’t seem to be consistent.
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• Are these observations consistent with the accepted value of the acceleration of gravity, which is 9.8 m / s^2?
answer/question/discussion: ->->->->->->->->->->->-> :
No, these accelerations are lower than 9.80 m/s^2.
#$&*
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About 20 minutes
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@& You need to refine your acceleration calculations, per my note. Of course you're also welcome to ask questions.*@