course phy121 I need the timeline for the delayed program, my girl friend has a tooth infection and I'm having to watch our daughter while doing these assignments and it is taking a little longer than I expected to do them. Thanks! 挘鼇唆讔妭轨冷屷仍嶛
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08:51:37 The Query program normally asks you questions about assigned problems and class notes, in question-answer-self-critique format. Since Assignments 0 and 1 consist mostly of lab-related activities, most of the questions on these queries will be related to your labs and will be in open-ended in form, without given solutions, and will not require self-critique. The purpose of this Query is to gauge your understanding of some basic ideas about motion and timing, and some procedures to be used throughout the course in analyzing our observations. Answer these questions to the best of your ability. If you encounter difficulties, the instructor's response to this first Query will be designed to help you clarify anything you don't understand. {}{}Respond by stating the purpose of this first Query, as you currently understand it.
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RESPONSE --> To assess our understanding of the ideas of motion and timing.
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08:53:47 If, as in the object-down-an-incline experiment, you know the distance an object rolls down an incline and the time required, explain how you will use this information to find the object 's average speed on the incline.
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RESPONSE --> 'dt / 'dt = av Lets say an object travels 26cm in 2 seconds. 26cm/2sec=13cm/sec confidence assessment: 3
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08:55:31 If an object travels 40 centimeters down an incline in 5 seconds then what is its average velocity on the incline? Explain how your answer is connected to your experience.
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RESPONSE --> 40cm / 5sec = 8cm/sec You use the distance traveled divided by the time taken to traverse the distance and it give you the average number of distance units traveled in one time unit. confidence assessment: 3
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08:57:44 If the same object requires 3 second to reach the halfway point, what is its average velocity on the first half of the incline and what is its average velocity on the second half?
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RESPONSE --> First half: (40cm/2) / 3sec = av 20cm / 3sec = 6.6667cm/sec Second half: (40cm/2) / 2sec = av 20cm / 2 sec = 10cm/sec confidence assessment: 3
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09:02:22 Using the same type of setup you used for the first object-down-an-incline lab, if the computer timer indicates that on five trials the times of an object down an incline are 2.42 sec, 2.56 sec, 2.38 sec, 2.47 sec and 2.31 sec, then to what extent do you think the discrepancies could be explained by each of thefollowing: {}{}a. The lack of precision of the TIMER program{}{}b. The uncertain precision of human triggering (uncertainty associated with an actual human finger on a computer mouse){}{}c. Actual differences in the time required for the object to travel the same distance.{}{}d. Differences in positioningthe object prior to release.{}{}e. Human uncertainty in observing exactly when the object reached the end of the incline.
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RESPONSE --> a. The program doens't have an extremely precise count as it's smallest unit is around .00156 of a second. b. there is no way you could depend on human timing to acceive repetitive results in an experiment like this. We can get close, but never exact. c. There should be very little time difference in each test. Much less than represented by the given times. d. Without an exact starting point made by a solid mounted stop of some kind, you can rarely place the object in the same place twice. e. The human eye has a sample rate the same as a camera (50cyc/sec I think?) so its entirely possible your eye just saw a ""black screen"" at the time the object reached the end of the incline. confidence assessment: 2
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09:05:37 How much uncertainty do you think each of the following would actually contribute to the uncertainty in timing a number of trials for the object-down-an-incline lab? {}{}a. The lack of precision of the TIMER program{}{}b. The uncertain precision of human triggering (uncertainty associated bLine$(lineCount) =with an actual human finger on a computer mouse){}{}c. Actual differences in the time required for the object to travel the same distance.{}{}d. Differences in positioning the object prior to release.{}{}e. Human uncertainty in observing exactly when the object reached the end of the incline.
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RESPONSE --> a. +/- .002 b. +/- .01 c. +/- .0001 d. +/- .1 e. +/- .01 confidence assessment: 2
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09:08:09 What, if anything, could you do about the uncertainty due to each of the following? Address each specifically. {}{}a. The lack of precision of the TIMER program{}{}b. The uncertain precision of human triggering (uncertainty associated with an actual human finger on a computer mouse){}{}c. Actualdifferences in the time required for the object to travel the same distance.{}{}d. Differences in positioning the object prior to release.{}{}e. Human uncertainty in observing exactly when the object reached the end of the incline.
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RESPONSE --> a. Find a more accurate/precise program b. use an optical eye to start the timer c. not much to correct for this. d. mark the position on the incline and use a block or something to release it. e. another optical eye. confidence assessment: 3
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09:10:35 According to the results of your introductory pendulum experiment, do you think doubling the length of the pendulum will result in half the frequency (frequency can be thought of as the number of cycles per minute), more than half or less than half?
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RESPONSE --> It would be closer to 2/3's of the original cycle according to my data. So more than half. confidence assessment: 3
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09:12:00 Note that for a graph of y vs. x, a point on the x axis has y coordinate zero and a point on the y axis has x coordinate zero. In your own words explain why this is so.
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RESPONSE --> If it is on the x-axis, then it has no movement on the y-axis and vise versa. The x-axis is the 0 or minimum value for the y-axis, and vise versa. confidence assessment: 2
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09:13:03 On a graph of frequency vs. pendulum length (where frequency is on the vertical axis and length on the horizontal), what would it mean for the graph to intersect the vertical axis (i.e., what would it mean, in terms of the pendulum and its behavior, if the line or curve representing frequency vs. length goes through the vertical axis)? What would this tell you about the length and frequency of the pendulum?
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RESPONSE --> You can get the pendulum too short to move. confidence assessment: 3
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09:14:39 On a graph of frequency vs. pendulum length, what would it mean for the graph to intersect the horizontal axis (i.e., what would it mean, in terms of the pendulum and its behavior, if the line or curve representing frequency vs. length goes through the horizontal axis)? What would this tell you about the length and frequency of the pendulum?
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RESPONSE --> That the pendulum was so long it couldn't complete a single cycle in the given cycle time. confidence assessment: 3
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09:16:43 If a ball rolls down between two points with an average velocity of 6 cm / sec, and if it takes 5 sec between the points, then how far apart are the points?
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RESPONSE --> av * 'dt = dist (6cm/sec) * 5sec = 30cm apart confidence assessment: 3
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09:17:07 On the average the ball moves 6 centimeters every second, so in 5 seconds it will move 30 cm. {}{}The formal calculation goes like this: {}{}We know that vAve = `ds / `dt, where vAve is ave velocity, `ds is displacement and `dt is the time interval. {}It follows by algebraic rearrangement that `ds = vAve * `dt.{}We are told that vAve = 6 cm / sec and `dt = 5 sec. It therefore follows that{}{}`ds = 6 cm / sec * 5 sec = 30 (cm / sec) * sec = 30 cm.{}{}The details of the algebraic rearrangement are asfollows:{}{}vAve = `ds / `dt. We multiply both sides of the equation by `dt:{}vAve * `dt = `ds / `dt * `dt. We simplify to obtain{}vAve * `dt = `ds, which we then write as{}`ds = vAve *`dt.{}{}Be sure to address anything you do not fully understand in your self-critique.
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RESPONSE --> I got it just fine. self critique assessment: 3
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09:18:43 You were asked to read the text and some of the problems at the end of the section. Tell me about something in the text you understood up to a point but didn't understand fully. Explain what you did understand, and ask the best question you can about what you didn't understand.
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RESPONSE --> I understood everything well enough to be able to apply it I believe. Some of the information we had covered in my Technical Mathmatics class earlier this week. confidence assessment: 1
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09:20:09 Tell me about something in the problems you understand up to a point but don't fully understand. Explain what you did understand, and ask the best question you can about what you didn't understand.
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RESPONSE --> I understood them well enough. confidence assessment: 0
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course phy121 I need the timeline for the delayed program, my girl friend has a tooth infection and I'm having to watch our daughter while doing these assignments and it is taking a little longer than I expected to do them. Thanks! 挘鼇唆讔妭轨冷屷仍嶛
......!!!!!!!!...................................
08:51:37 The Query program normally asks you questions about assigned problems and class notes, in question-answer-self-critique format. Since Assignments 0 and 1 consist mostly of lab-related activities, most of the questions on these queries will be related to your labs and will be in open-ended in form, without given solutions, and will not require self-critique. The purpose of this Query is to gauge your understanding of some basic ideas about motion and timing, and some procedures to be used throughout the course in analyzing our observations. Answer these questions to the best of your ability. If you encounter difficulties, the instructor's response to this first Query will be designed to help you clarify anything you don't understand. {}{}Respond by stating the purpose of this first Query, as you currently understand it.
......!!!!!!!!...................................
RESPONSE --> To assess our understanding of the ideas of motion and timing.
.................................................
......!!!!!!!!...................................
08:53:47 If, as in the object-down-an-incline experiment, you know the distance an object rolls down an incline and the time required, explain how you will use this information to find the object 's average speed on the incline.
......!!!!!!!!...................................
RESPONSE --> 'dt / 'dt = av Lets say an object travels 26cm in 2 seconds. 26cm/2sec=13cm/sec confidence assessment: 3
.................................................
......!!!!!!!!...................................
08:55:31 If an object travels 40 centimeters down an incline in 5 seconds then what is its average velocity on the incline? Explain how your answer is connected to your experience.
......!!!!!!!!...................................
RESPONSE --> 40cm / 5sec = 8cm/sec You use the distance traveled divided by the time taken to traverse the distance and it give you the average number of distance units traveled in one time unit. confidence assessment: 3
.................................................
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08:57:44 If the same object requires 3 second to reach the halfway point, what is its average velocity on the first half of the incline and what is its average velocity on the second half?
......!!!!!!!!...................................
RESPONSE --> First half: (40cm/2) / 3sec = av 20cm / 3sec = 6.6667cm/sec Second half: (40cm/2) / 2sec = av 20cm / 2 sec = 10cm/sec confidence assessment: 3
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09:02:22 Using the same type of setup you used for the first object-down-an-incline lab, if the computer timer indicates that on five trials the times of an object down an incline are 2.42 sec, 2.56 sec, 2.38 sec, 2.47 sec and 2.31 sec, then to what extent do you think the discrepancies could be explained by each of thefollowing: {}{}a. The lack of precision of the TIMER program{}{}b. The uncertain precision of human triggering (uncertainty associated with an actual human finger on a computer mouse){}{}c. Actual differences in the time required for the object to travel the same distance.{}{}d. Differences in positioningthe object prior to release.{}{}e. Human uncertainty in observing exactly when the object reached the end of the incline.
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RESPONSE --> a. The program doens't have an extremely precise count as it's smallest unit is around .00156 of a second. b. there is no way you could depend on human timing to acceive repetitive results in an experiment like this. We can get close, but never exact. c. There should be very little time difference in each test. Much less than represented by the given times. d. Without an exact starting point made by a solid mounted stop of some kind, you can rarely place the object in the same place twice. e. The human eye has a sample rate the same as a camera (50cyc/sec I think?) so its entirely possible your eye just saw a ""black screen"" at the time the object reached the end of the incline. confidence assessment: 2
.................................................
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09:05:37 How much uncertainty do you think each of the following would actually contribute to the uncertainty in timing a number of trials for the object-down-an-incline lab? {}{}a. The lack of precision of the TIMER program{}{}b. The uncertain precision of human triggering (uncertainty associated bLine$(lineCount) =with an actual human finger on a computer mouse){}{}c. Actual differences in the time required for the object to travel the same distance.{}{}d. Differences in positioning the object prior to release.{}{}e. Human uncertainty in observing exactly when the object reached the end of the incline.
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RESPONSE --> a. +/- .002 b. +/- .01 c. +/- .0001 d. +/- .1 e. +/- .01 confidence assessment: 2
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09:08:09 What, if anything, could you do about the uncertainty due to each of the following? Address each specifically. {}{}a. The lack of precision of the TIMER program{}{}b. The uncertain precision of human triggering (uncertainty associated with an actual human finger on a computer mouse){}{}c. Actualdifferences in the time required for the object to travel the same distance.{}{}d. Differences in positioning the object prior to release.{}{}e. Human uncertainty in observing exactly when the object reached the end of the incline.
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RESPONSE --> a. Find a more accurate/precise program b. use an optical eye to start the timer c. not much to correct for this. d. mark the position on the incline and use a block or something to release it. e. another optical eye. confidence assessment: 3
.................................................
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09:10:35 According to the results of your introductory pendulum experiment, do you think doubling the length of the pendulum will result in half the frequency (frequency can be thought of as the number of cycles per minute), more than half or less than half?
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RESPONSE --> It would be closer to 2/3's of the original cycle according to my data. So more than half. confidence assessment: 3
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09:12:00 Note that for a graph of y vs. x, a point on the x axis has y coordinate zero and a point on the y axis has x coordinate zero. In your own words explain why this is so.
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RESPONSE --> If it is on the x-axis, then it has no movement on the y-axis and vise versa. The x-axis is the 0 or minimum value for the y-axis, and vise versa. confidence assessment: 2
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09:13:03 On a graph of frequency vs. pendulum length (where frequency is on the vertical axis and length on the horizontal), what would it mean for the graph to intersect the vertical axis (i.e., what would it mean, in terms of the pendulum and its behavior, if the line or curve representing frequency vs. length goes through the vertical axis)? What would this tell you about the length and frequency of the pendulum?
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RESPONSE --> You can get the pendulum too short to move. confidence assessment: 3
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09:14:39 On a graph of frequency vs. pendulum length, what would it mean for the graph to intersect the horizontal axis (i.e., what would it mean, in terms of the pendulum and its behavior, if the line or curve representing frequency vs. length goes through the horizontal axis)? What would this tell you about the length and frequency of the pendulum?
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RESPONSE --> That the pendulum was so long it couldn't complete a single cycle in the given cycle time. confidence assessment: 3
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09:16:43 If a ball rolls down between two points with an average velocity of 6 cm / sec, and if it takes 5 sec between the points, then how far apart are the points?
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RESPONSE --> av * 'dt = dist (6cm/sec) * 5sec = 30cm apart confidence assessment: 3
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09:17:07 On the average the ball moves 6 centimeters every second, so in 5 seconds it will move 30 cm. {}{}The formal calculation goes like this: {}{}We know that vAve = `ds / `dt, where vAve is ave velocity, `ds is displacement and `dt is the time interval. {}It follows by algebraic rearrangement that `ds = vAve * `dt.{}We are told that vAve = 6 cm / sec and `dt = 5 sec. It therefore follows that{}{}`ds = 6 cm / sec * 5 sec = 30 (cm / sec) * sec = 30 cm.{}{}The details of the algebraic rearrangement are asfollows:{}{}vAve = `ds / `dt. We multiply both sides of the equation by `dt:{}vAve * `dt = `ds / `dt * `dt. We simplify to obtain{}vAve * `dt = `ds, which we then write as{}`ds = vAve *`dt.{}{}Be sure to address anything you do not fully understand in your self-critique.
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RESPONSE --> I got it just fine. self critique assessment: 3
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09:18:43 You were asked to read the text and some of the problems at the end of the section. Tell me about something in the text you understood up to a point but didn't understand fully. Explain what you did understand, and ask the best question you can about what you didn't understand.
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RESPONSE --> I understood everything well enough to be able to apply it I believe. Some of the information we had covered in my Technical Mathmatics class earlier this week. confidence assessment: 1
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09:20:09 Tell me about something in the problems you understand up to a point but don't fully understand. Explain what you did understand, and ask the best question you can about what you didn't understand.
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RESPONSE --> I understood them well enough. confidence assessment: 0
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