phy121
Your 'cq_1_03.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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A ball starts with velocity 0 and accelerates down a ramp of length 30 cm, covering the distance in 5 seconds.
What is its average velocity?
30cm / 5s = vAve of 6cm/sec
If the acceleration of the ball is uniform then its average velocity is equal to the average of its initial and final velocities.
true
You know its average velocity, and you know the initial velocity is zero. What therefore must be the final velocity?
x=Final Velocity (vF)
(vI + vF) / 2 = vAve
(0 + x) / 2 = 6
(0 + x) = 6 * 2
0 + x = 12
x = 12 - 0
vF = 12m/s
By how much did its velocity therefore change?
increased at a rate of 2.4m/s/s for 5sec for a vF of 12m/s
At what average rate did its velocity change with respect to clock time?
2.4m/s/s
What would a graph of its velocity vs. clock time look like? Give the best description you can.
velocity on the y-axis
time on the x-axis
line with a slope of +2.4 from (0,0) through (5,12)
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10 min
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&#This looks very good. Let me know if you have any questions. &#