course phy121
Reason out the quantities v0, vf, Dv, vAve, a, Ds and Dt: If an object’s initial velocity is 12 cm/s, and it accelerates uniformly through 140 cm in 10 seconds, then what is its final velocity?
vF = 16cm/sec
vAve = `ds / `dt = 140cm / 10s = 14cm/s
vAve = (v0 + vF) / 2
(2 * vAve) - v0 = vF
(2 * 14cm/s) - 12cm/s = vF
vF = 16cm/s
Using the equations which govern uniformly accelerated motion determine vf, v0, a, Ds and Dt for an object which
accelerates through a distance of 140 cm, ending with velocity 12 cm/s and accelerating at .4 cm/s/s.
vF=12cm/s
v0=1.79cm/s
a=.4cm/s/s
`ds=140cm
`dt=10.15sec"
Very good responses. Let me know if you have questions.