phy121
Your 'cq_1_7.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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A ball falls freely from rest at a height of 2 meters. Observations indicate that the ball reaches the ground in .64 seconds.
Based on this information what is its acceleration?
2m / .64sec = 3.13m/s
(v0 + vF) / 2 = vAve
(vAve * 2) - v0 = vF
(3.13 *2) - 0 = 6.26m/s
6.26m/s / .64sec = 9.78m/s/s
Is this consistent with an observation which concludes that a ball dropped from a height of 5 meters reaches the ground in
1.05 seconds?
5m / 1.05sec = 4.76m/s
4.76 * 2 - 0 = 9.52m/s
9.52m/s / 1.05sec = 9.07m/s/s
Are these observations consistent with the accepted value of the acceleration of gravity, which is 9.8 m / s^2?
The first one is consistent with the value, assuming some error in measurements. The second one is off by quite a bit, and unless larger than normal error is accepted, would not be consistent.
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10min
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&#This looks very good. Let me know if you have any questions. &#