course phy121
A ball starting from rest rolls 10 cm down an incline on which its acceleration is 22 cm/s2, then onto a second incline 35 cm long on which its acceleration is constant, and on which it spends 1.359 seconds.
How much time does it spend on the first incline and what is its acceleration on the second?
vF = sqrt[0^2 + (2*22) * 10]
vF = 20.98cm/s
vAve = (0 + 20.98) / 2
vAve = 10.49cm/s
`dt = 10cm / 10.49cm/s
`dt = .953sec
Using 20.98cm/s as v0 for the second incline, we find that the vF is 30.52. Dividing the difference between vF and v0 by the `dt we get a=7.02m/s/s."
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