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course Phy 201
2/16 3
Reason out the quantities v0, vf, Dv, vAve, a, Ds and Dt: If an object’s velocity changes at a uniform rate from 11 cm/s to 15 cm/s as it travels 117 cm, then what is the average acceleration of the object?
Using the equations which govern uniformly accelerated motion determine vf, v0, a, Ds and Dt for an object which accelerates through a distance of 117 cm, starting from velocity 11 cm/s and accelerating
at .444 cm/s/s.
1.
v0 = 11cm/s
vf = 15cm/s
'dv = 4cm/s
vAve = 13cm/s
a = .44 cm/s^2
'ds = 117cm
'dt = 9s
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That's not the order in which the quantities would be reasoned out. I expect you know how to reason them out, but on a test be sure you show the reasoning. You're welcome to resubmit if you're not sure; otherwise it isn't necessary.
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2.
v0 = 11cm/s
a = .444cm/s^2
'ds = 117cm
'dt = 'dV/.444cm/s = 9 seconds
vf^2 = v0^2 + 2a'dt
vf^2 = 11^2 + .88 * 117
vf^2 = 121cm/s + 102.96
vf^2 = 224cm/s
vf = 15cm/s
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Good.
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&#Your work looks good. See my notes. Let me know if you have any questions. &#