CrystalCall

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course mth 151

Jan.24, 201410:39 a.m

assignment 1" "Question: `q001. Note that there are 5 questions in this assignment.

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Question: `q001. Let A stand for the collection of all whole numbers which have at least one even digit (e.g., 237, 864, 6, 3972 are in the collection, while 397, 135, 1, 9937 are not). Let A ' stand for the collection of all whole numbers which are not in the collection A. Let B stand for the collection { 3, 8, 35, 89, 104, 357, 4321 }.

• What numbers do B and A have in common?

• What numbers do B and A' have in common?

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Your solution:

B and A =237, 864, 6, 3972, 8, 89, 104, 4321

B and A’ = 3, 35, 397, 1, 9937, 357

confidence rating #$&*:

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Given Solution:

Of the numbers in B, 8, 89, 104, 4321 each have at least one even digit and so are common to both sets.

Of the numbers in B, 3 is odd, both of the digits in the number 35 are odd, as are all three digits in the number 357. All three of these numbers are therefore in A ' .

STUDENT QUESTION

In the second part of the question you said BOTH of these numbers are therefore in A’, so does that mean that 3 is not and

if so then why not? Also what does the ‘(is it an apostrophe?) in A’ stand for or is in just a means of separation?

INSTRUCTOR RESPONSE

Of the numbers in B, the number 3 is in A ', the number 35 is in A ' and the number 357 is in A ' .

The apostrophe (you identified it correctly) indicates that you are looking for elements that are NOT in the set. This is in relation to the statement in the problem: Let A ' stand for the collection of all whole numbers which are not in the collection A.

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Self-critique (if necessary):

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Self-critique Rating: ok

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Question: `q002. I have in a room 8 people with dark hair brown, 2 people with bright red hair, and 9 people with light brown or blonde hair. Nobody has more than one hair color. Is it possible that there are exactly 17 people in the room?

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Your solution:

no, it’s not possible to have exactly 17 people in the room unless some share the same hair color and since the problem states that no one has more than one hair color, the answer is no.

confidence rating #$&*:m always a little less confident in my answers until I compare them with the given solution. I always kinda fear that I am missing something.

@&

Good.

That is, of course, one of the primary reasons I provide the solutions.

*@

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Given Solution: a If we assume that dark brown, light brown or blonde, and bright red hair are mutually exclusive (i.e., someone can't be both one category and another, much less all three), then we have at least 8 + 2 + 9 = 19 people in the room, and it is not possible that we have exactly 17.

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Self-critique (if necessary):

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Self-critique Rating: ok

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Question: `q003. I have in a room 6 people with dark hair and 10 people with blue eyes. There are only 14 people in the room. But 10 + 6 = 16, which is more than 14. How can this be?

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Your solution: I believe that at least 2 people have both dark hair and blue eyes

confidence rating #$&*:

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Given Solution: `a The key here is that there is nothing mutually exclusive about these categories-a person can have blue eyes as well as dark hair. So if there are 2 people in the room who have dark hair and blue eyes, which is certainly possible, then when we add 10 + 6 = 16 those two people would be counted twice, once among the 6 blue-eyed people and once among the 10 dark-haired people. So the 16 we get would be 2 too high. To get the correct number we would have to subtract the 2 people who were counted twice to get 16 - 2 = 14 people.

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Self-critique (if necessary):

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Self-critique Rating: ok

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Question: `q004. In a set of 100 child's blocks 60 blocks are cubical and 40 blocks are cylindrical. 30 of the blocks are red and 20 of the red blocks are cubical. How many of the cylindrical blocks are red?

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Your solution:

10 cylindrical are red

confidence rating #$&*:

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Given Solution: `a Of the 30 red blocks 20 are cubical, so the rest must be cylindrical. This leaves 10 red cylindrical blocks.

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Self-critique (if necessary):

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Self-critique Rating: ok

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Question: `q005. If there are 30 blue marbles and 35 small marbles in a box containing 50 marbles. What is the smallest possible number of small blue marbles? Is it possible that the number of small blue marbles is greater than this?

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Your solution:

No, there cannot be a greater number of blue marbles because the smallest possible number of small blue marbles would be 30 being that there are only 30 blue marbles in the pack of 50.

confidence rating #$&*:

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Self-critique Rating: ok

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Self-critique (if necessary):

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Self-critique rating:

&#Your work looks good. Let me know if you have any questions. &#

CrystalCall

#$&*

course mth 151

Jan 24, 201411:26 a.m.

Assignment 2

the sketches in the given solution didn't come through on the submit work form. Did you want me to send the document that has the given solution sketches on them through the SEND files instructions?" "Question: `q001. We can represent the collection consisting of the letters a, b, c, d, e, f by a circle in which we write these letters. If we have another collection consisting of the letters a, c, f, g, k, we could represent it also by a circle containing these letters. If both collections are represented in the same diagram, then since the two collections have certain elements in common the two circles should overlap.

Sketch a diagram with two overlapping circles. The two circles will create four regions. The first region is the region where the circles overlap. The second region is the one outside of both circles. The third region is the part of the first circle that doesn't include the overlap. The fourth region is the part of the second circle that doesn't include the overlap. Number these regions with the Roman numerals I (the overlap), II (first circle outside overlap), III (second circle outside overlap) and IV (outside both circles).

Let the first circle contain the letters in the first collection and let the second circle contain the letters in the second collection, with the letters common to both circles represented in the overlapping region.

Which letters, if any, go in region I, which in region II, which in region III and which in region IV?

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Your solution:

In Region I: A, C, F

In Region II: B, D, E

In Region III: G, K

In Region IV: nothing

confidence rating #$&*: I can sketch this on paper but not sure how to do this on the computer. I was pretty confident though in my solution.

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Given Solution: The circles would appear and be labeled as below:

The letters a, c and f go in the overlapping region, which we called Region I. The remaining letters in the first collection are b, d, and e, and they go in the part of the first circle that does not include the overlapping region, which we called Region II. The letters g and k go in the part of the second circle that does not include the overlapping region (Region III). There are no letters in Region IV.

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Self-critique (if necessary):

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Self-critique Rating: ok

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Question: `q002. Suppose that we have a total of 35 people in a room. Of these, 20 have dark hair and 15 have bright eyes. There are 8 people with dark hair and bright eyes.

Draw two circles, one representing the dark-haired people and the other representing the bright-eyed people. Represent the dark-haired people without bright eyes by writing this number in the part of the first circle that doesn't include the overlap (region II). Represent the number of bright-eyed people without dark hair by writing this number in the part of the second circle that doesn't include the overlap (region III). Write the appropriate number in the overlap (region I).

How many people are included in the first circle, and how many in the second?

How many people are included in both circles?

How many of the 35 people are not included in either circle?

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Your solution:

First Circle: 8

Second Circle: 12

Third Circle:7

Outside the Circles: 8

8+12+7+8 =35

confidence rating #$&*:

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Given Solution:

These numbers are represented in the circles below.

• A number on the boundary of a circle indicates the total number in that circle, so the figure represents 20 individuals in circle A and 15 in circle B. The number 35 on the boundary of the entire figure represents the total number of individuals in the room, which in this case is 35.

• A number inside one of the regions I, II, III, IV represents the number in that region. The 8 having both dark hair and bright eyes will occupy the overlap between the circles (region I).

Of the 15 people with bright eyes, 8 also have dark hair so the other 7 do not have dark hair, and this number will be represented by the part of the second circle that doesn't include the overlap (region III). This is indicated by the number 7 inside region III in the figure below.

Of the 20 dark-haired people in the preceding example, 8 also have bright eyes. This leaves 12 dark-haired people for that part of the circle that doesn't include the overlap (region II).

We have accounted for 12 + 8 + 7 = 27 people. This leaves 35-27 = 8 people who are not included in either of the circles. The number 8 can be written outside the two circles (region IV) to indicate the 8 people who have neither dark hair nor bright eyes, as is indicated by the number 8 in region IV in the figure below:

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Self-critique (if necessary):

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Self-critique Rating: ok

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Question: `q003. Suppose there are 200 people in a hall, 140 having dark hair, 90 having short hair and 50 having hair which is neither dark nor short. Sketch a diagram like the ones above, specify how many people are in each of the four regions and describe the people in each region.

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Your solution:

Overlap Region: 10 people with both short, dark hair

Region one: 50 Dark haired people

Region two: 90 Short haired peopled

Region outside of circles: 50 people who have neither dark nor short hair

90+10+50+50 = 200 people

confidence rating #$&*:

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Self-critique Rating: ok

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#*&!

&#Your work looks good. Let me know if you have any questions. &#