course PHY 121
Is this where I need to submit this or was I suppose to email this as an attachment?
This writeup works just find with the form.
You did well here except for a reversal at the very end. See my note and be sure you understand.
If you have questions let me know.
s this where I need to submit this or was I suppose to email this as an attachment?" "I would like some feedback as to whether I completed this mini experiment correctly; because I just completed the data and questions you gave I could not figure out what quantities to put in the table.Mini Experiment 1: Rolling an object down an
• Description
o I used the marble from my lab kit and a hardback Math textbook. I propped one end of the math textbook by 2.5 cm, therefore the higher end was 2.5 cm higher than the other. I found it difficult to try to release the marble and time the distance using my pulse, so I timed the distance using seconds. The ramp was 23 cm long.
• Data
o Difference in height from one end to the other: 2.5 cm
o Distance rolled by the object from one end to the other: 23 cm
o Time required .78 sec
• Analysis
o By how many centimeters did the position of the object change from release to the end of the ramp? We call the change in the position `ds.
The position of the marble changed by 2.5 cm as far as the height. The length that it traveled was 23 cm. I am not sure if this is what you are looking for. However it changed from the top of the incline to the bottom by 2.5 cm. Where does the change in position `ds come into play?
You actually have a couple of possibilities for `ds. One is the 2.5 cm change in vertical position, which we might denote `ds_y.
However the intent here is to use `ds along the ramp, which is the 23 cm you use below.
o How much higher was the high end of the ramp compared to the low end?
The high end of the ramp was 2.5 cm higher than the lower end of the ramp.
o What was the duration of the time interval required for the object to change its position from the top to the bottom of the ramp? We call this time interval `dt and it represent the change in clock time from the instant the object was released at the top of the ramp to the instant it reached the bottom.
It took the marble .78 sec to get down the ramp.
o At what average rate with respect to time did the position of the object change as it moved from the top to the bottom of the ramp? Recall that average rate of change of one quantity with respect to another is
average rate = change in first quantity / change in second quantity.
.78sec / 23cm = 0.0339 sec/cm
average rate of change of one quantity with respect to another is
average rate = change in first quantity / change in second quantity.
The 'second quantity' in this statement is modified by the phrase 'with respect to'.
So you have these two quantities reversed and the requested average rate would be 23 cm / (.78 sec) = etc..