course PHY121
Let me know if this completes the requirements for the video experiment # 12. I have also email a copy of the graphs to your email address.
What you show here is good. However I need the rest of your explanations, including the calculation of graph slope. That calculation should include documentation of the points on your straight-line approximation that were used as a basis for calculating the graph slope. If you have questions on what this means, let me know.
Copy and paste your entire writeup into the form and send it again.
Let me know if this completes the requirements for the video experiment # 12. I have also email a copy of the graphs to your email address."
Calculations of mass 15 * 1.2 = 18g /1000 = 0.018kg 12 * 1.2 = 14.4g / 1000 = 0.0144kg 9 * 1.2 = 10.8g / 1000 = 0.0108kg 6 * 1.2 = 7.2 g / 1000 = 0.0072kg 3 * 1.2 = 3.6g / 1000 = 0.
Calculations of Force F = m * a 0.018kg * 9.8m/s^2 = .1764 N 0.0144kg * 9.8m/s^2 = .14112 N 0.0108kg * 9.8m/s^2 = .10584 N 0.0072kg * 9.8m/s^2 = .07056 N 0.0036g * 9.8m/s^2 = .03528 N
Effective Slope Force
0.0293 0.1764
0.0232 0.14112
0.0157 0.10584
0.0101 0.07056
0.0026 0.03528
I have attached further explanations and the graphs to your email address.