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PHY 121
Your 'cq_1_06.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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For each situation state which of the five quantities v0, vf, `ds, `dt and a are given, and give the value of each.
A ball accelerates uniformly from 10 cm/s to 20 cm/s while traveling 45 cm.
answer/question/discussion: ->->->->->->->->->->->-> n:
v0 = 10cm/sec
v_f = 20cm/sec
`ds = 45cm
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A ball accelerates uniformly at 10 cm/s^2 for 3 seconds, and at the end of this interval is moving at 50 cm/s.
answer/question/discussion: ->->->->->->->->->->->-> n:
a = 10cm/sec^2
`dt = 3sec
Vf = 50cm/sec
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A ball travels 30 cm along an incline, starting from rest, while accelerating at 20 cm/s^2.
answer/question/discussion: ->->->->->->->->->->->-> n:
v_0 = 0cm/sec
a = 20cm/sec^2
`ds = 30cm
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Then for each situation answer the following:
Is it possible from this information to directly determine vAve?
answer/question/discussion: ->->->->->->->->->->->-> n:
v0 = 10cm/sec
vf = 20cm/sec
`ds = 45cm
Yes. vAve = (vf+v0)/2
a = 10cm/sec^2
`dt = 3sec
Vf = 50cm/sec
No, not without calculating other values first.
v_0 = 0cm/sec
a = 20cm/sec^2
`ds = 30cm
Not without calculating vf first. vf^2 = v0^2 + 2 a `ds.
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Is it possible to directly determine `dv?
answer/question/discussion: ->->->->->->->->->->->-> n:
v0 = 10cm/sec
vf = 20cm/sec
`ds = 45cm
Yes. `dv = (vf-v0)
a = 10cm/sec^2
`dt = 3sec
Vf = 50cm/sec
Only if we calculate v0 by solving a = (vf-v0)/`dt for v0 first.
v_0 = 0cm/sec
a = 20cm/sec^2
`ds = 30cm
Not without solving for vf first.
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*#&!
&#Very good responses. Let me know if you have questions. &#