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PHY 121
Your 'cq_1_10.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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A pendulum requires 2 seconds to complete a cycle, which consists of a complete back-and-forth oscillation (extreme point to equilibrium to opposite extreme point back to equilibrium and finally to the original extreme point). As long as the amplitude of the motion (the amplitude is the distance from the equilibrium position to the extreme point) is small compared to the length of the pendulum, the time required for a cycle is independent of the amplitude.
How long does it take to get from one extreme point to the other, how long from an extreme point to equilibrium, and how long to go from extreme point to equilibrium to opposite extreme point and back to equilibrium?
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answer/question/discussion: ->->->->->->->->->->->-> n:
1 second from first extreme to the second,
.5 seconds from extreme to equilibrium
1.5 seconds from extreme to equilibrium, opposite extreme and back to equilibrium
What reasonable assumption did you make to arrive at your answers?
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answer/question/discussion: ->->->->->->->->->->->-> n:
If the time/cycle of the pendulum is independent of its amplitude, I assume that the two second cycle could be broken into even .5 second intervals. .5 from extreme to equilibrium, .5 from equilibrium to extreme, etc.
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10m
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#$&* self-critique
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&#Very good responses. Let me know if you have questions. &#