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PHY 121
Your 'cq_1_12.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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Masses of 5 kg and 6 kg are suspended from opposite sides of a light frictionless pulley and are released.
What will be the net force on the 2-mass system and what will be the magnitude and direction of its acceleration?
answer/question/discussion: ->->->->->->->->->->->-> n:
a = 9.8m/sec^2
m = 5kg and 6kg
F_net1 = (9.8m/sec^2)(5kg)
=49m*kg/sec^2 = 49N
F_net2 = (9.8m/sec^2)(6kg)
=58.8m*kg/sec^2 = 58.8N
F_net = 58.8N - 49N = 9.8N
A = F_net/m
=9.8N/11kg
=(9.8m*kg/sec^2)/(11kg)
=.89m/sec^2
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If you give the system a push so that at the instant of release the 5 kg object is descending at 1.8 meters / second, what will be the speed and direction of motion of the 5 kg mass 1 second later?
answer/question/discussion: ->->->->->->->->->->->-> n:
a = .89m/sec^2
Direct reasoning suggests that it would take about 2 seconds for the systems acceleration to negate the 5kg object’s initial velocity. At 1 second, the motion would still be in the direction of the push and its velocity should be .5 of the original or .9m/sec
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During the first second, are the velocity and acceleration of the system in the same direction or in opposite directions, and does the system slow down or speed up?
answer/question/discussion: ->->->->->->->->->->->-> n:
During the first second the velocity is in the opposite direction of acceleration and the system will slow from the initial velocity of 1.8m/sec until at about 2 seconds later, the system has negated the initial push and then it will begin moving in the direction of acceleration.
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