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PHY 121
Your 'cq_1_19.3' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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An object moving in the direction 120 degrees (as measured counterclockwise to the positive x axis) encounters a net force whose direction is 270 degrees.
Sketch the force and its component along the line of motion, as well as its component perpendicular to the line of motion.
answer/question/discussion: ->->->->->->->->->->->-> n:
The direction vector is pointing in the -x +y direction. The force vector is aligned with the -y axis.
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Suppose you are facing in the direction of motion. Do you perceive the component of the force along the line of motion to be forward or backward? It this component in the direction of motion or opposite to the direction of motion?
answer/question/discussion: ->->->->->->->->->->->-> n:
The force would not be perfectly reflected, but most of the force would be felt as backward and opposite the direction of motion.
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Will the object speed up, slow down or maintain a constant speed?
answer/question/discussion: ->->->->->->->->->->->-> :
Since most of the force is in the opposite direction of motion, it would slow down
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If you are facing in the direction of motion, then the line perpendicular to the direction of motion will run to your right and to your left. Is the component of the force perpendicular to the line of motion directed to the right or to the left?
answer/question/discussion: ->->->->->->->->->->->-> n:
The force is directed at 270d and the object facing 120d
The force would be directed to the left since its theta angle to the force is less than the right’s.
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Will the object veer to the right, to the left or maintain straight-line motion?
answer/question/discussion: ->->->->->->->->->->->-> n:
The object would be pushed to the left
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Which is greater in magnitude, the component of the force along the line of motion or the component perpendicular to the line of motion?
answer/question/discussion: ->->->->->->->->->->->-> n:
120d+270d = 390d (30d)
30d = 90d from line of motion
120d + (360d-270d) = 90d
=210d
=80d from line of motion
The force along the line of motion is greater
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&#Your work looks very good. Let me know if you have any questions. &#