Assignment 3 textbook

course MTH 151

Your work on this assignment is good. See my note confirming that you were right on that last problem.

Let me know if anything is unclear.

ÃÔ™{¦ˆÈúzÞûݱ|ÍðoêsÎÝ㎟…v�ÓÉassignme –¨x¶è€Õ±îyrÝÝz™WÌ�L™à�äܪ Liberal Arts Mathematics I 01-25-2006

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23:40:12 Query 2.3.15 (Y ^ Z')U X, univ={a,..g}, X={a,c,e,g}, Y = {a,b,c}, Z = {b, ..., f} What is the set (Y ^ Z')U X?

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RESPONSE --> # 19 from the book: Z' = {a,g} so (Y ^ Z') = {a,b,c} ^ {a,g} = {a} {a} U X = {a,c,e,g}

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23:40:30 **Z' = {a,g}, the set of all elements of the universal set not in Z. Y ^ Z' = {a}, since a is the only element common to both Y and Z'. So (Y ^ Z') U X = {a, c, e, g}, the set of all elements which lie in at least one of the sets (Y ^ Z') U X. **

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RESPONSE --> right

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23:41:30 Give the intersection of the two sets Y and Z'

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RESPONSE --> Y ^ Z' = {a}

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23:41:40 **Z' = {a,g}, the set of all elements of the universal set not in Z. Y ^ Z' = {a}, since a is the only element common to both Y and Z'.**

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RESPONSE --> ok

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23:42:48 Query 2.3.30 describe in words (A ^ B' ) U (B ^ A')

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RESPONSE --> The set of all elements in A and not in B, or are in B but not in A.

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23:43:27 ** a description, not using a lot of set-theoretic terms, of (A ^ B' ) U (B ^ A') would be, all the elements that are in A and not in B, or that are not in A and are in B Or you might want to say something like 'elements which are in A but not B OR which are in B but not A'. STUDENT SOLUTION WITH INSTRUCTOR COMMENT:everything that is in set A and not in set B or everything that is in set B and is not in set A. INSTRUCTOR COMMENT: I'd avoid the use of 'everything' unless the word is necessary to the description. Otherwise it's likely to be misleading. **

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RESPONSE --> right

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23:43:51 2.3.51 always or not always true: n(A U B) = n(A)+n(B)

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RESPONSE --> not always

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23:45:22 ** This conclusion is contradicted by many examples, including the one of the dark-haired and bright-eyed people in the q_a_. Basically n(A U B) isn't equal to n(A) + n(B) if there are some elements which are in both sets--i.e., in the intersection. } MORE DETAIL: The statement can be either true or false, depending on the sets A and B; it is not always true. The statement n(A U B) = n(A)+n(B) means that the number of elements in A U B is equal to the sum of the number of elements in A and the number of elements in B. The statement would be true for A = { c, f } and B = { a, g, h} because A U B would be { a, c, f, g, h} so n(A U B) = 5, and n(A) + n(B) = 2 + 3 = 5. The statement would not be true for A = { c, f, g } and B = { a, g, h} because A U B would be the same as before so n(AUB) = 5, while n(A) + n(B) = 3 + 3 = 6. The precise condition for which the statement is true is that A and B have nothing in common. In that case n(A U B) = n(A) + n(B). A more precise mathematical way to state this is to say that n(A U B) = n(A) + n(B) if and only if the intersection A ^ B of the two sets is empty. **

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RESPONSE --> ok

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23:48:48 Query 2.3.60 X = {1,3,5}, Y = {1,2,3}. Find (X ^ Y)' and X' U Y'.

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RESPONSE --> A rule in our book states that (A ^ B)' = A' U B', hence (X ^ Y)' = X' U Y' X' U Y' = {2,4,5}

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23:49:15 ** X ^ Y = {1,3} so (X ^ Y) ' = {1,3}' = {2, 4, 5}. (X ' U Y ' ) = {2, 4} U {4, 5} = {2, 4, 5} The two resulting sets are equal so a reasonable conjecture would be that (X ^ Y)' = X' U Y'. **

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RESPONSE --> ok

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23:51:31 2.3.72 A = {3,6,9,12}, B = {6,8}.

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RESPONSE --> A X B = {(3,6)(3,8)(6,6)(6,8)(9,6)(9,8)(12,6)(12,8)} B X A = {(6,3)(6,6)(6,9)(6,12)(8,3)(8,6)(8,9)(8,12)}

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23:52:34 ** (A X B) = {(3,6),(3,8),(6,6),(6,8),(9,6),(9,8),(12,6), (12,8)} (B X A) = (6,3),(6,6),(6,9),(6,12),(8,3),(8,6),(8,9),(8,12)} How is n(A x B) related to n(A) and n(B)? n(S) stands for the number of elements in the set S, i.e., its cardinality. n(A x B) = n(A) * n(B) **

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RESPONSE --> ok

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23:53:12 2.3.84 Shade A U B

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RESPONSE --> on my diagram all of A is shaded as is all of B

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23:53:21 ** everything in A and everything in B would be shaded. The rest of the universal set (the region outside A and B but still in the rectangle) wouldn't be. **

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RESPONSE --> right

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23:56:04 Query 2.3.100 Shade (A' ^ B) ^ C

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RESPONSE --> The only areas shaded are the overlap between B and C and the area of C not included in A or the overlap b/w A and B. I can't draw on here so I hope my exlpanation makes sense.

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23:56:42 ** you would have to shade every region that lies outside of A and also inside B and also inside C. This would be the single region in the overlap of B and C but not including any part of A. Another way to put it: the region common to B and C, but not including any of A **

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RESPONSE --> got it!

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23:59:42 Describe the shading of the set (A ^ B)' U C.

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RESPONSE --> (A ^ B)' = A' U B' I think the only area shaded is the part of C that doesn't overlap with any other region.

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00:02:44 ** All of C would be shaded because we have a union with C, which will include all of C. Every region outside A ^ B would also be shaded. A ^ B is the 'overlap' region where A and B meet, and only this 'overlap' would not be part of (A ^ B) '. The 'large' parts of A and B, as well as everything outside of A and B, would therefore be shaded. Combining this with the shading of C the only the part of the diagram not shaded would be that part of the 'overlap' of A and B which is not part of C. **

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RESPONSE --> I made this more complicated than neccessary. I drew the correct diagram and will go over it.

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00:03:09 2.3.114 Largest area of A shaded (sets A,B,C). Write a description using A, B, C, subset, union, intersection symbols, ', - for the shaded region.

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RESPONSE --> A ^ B' ^ C'

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00:04:14 ** Student Answer and Instructor Response: (B'^C')^A Instructor Response: Good. Another alternative would be A - (B U C ), and others are mentioned below. COMMON ERROR: A ^ (B' U C') INSTRUCTOR COMMENT: This is close but A ^ (B' U C') would contain all of B ^ C, including a part that's not shaded. A ^ (B U C)' would be one correct answer. **

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RESPONSE --> ok, so mine is correct?

It sure is. Good job.

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