Phy 121
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The problem:
A ball accelerates at 8 cm/s^2 for 3 seconds, starting with velocity 12 cm/s.
• What will be its velocity after the 3 seconds has elapsed?
answer/question/discussion: ->->->->->->->->->->->-> :
The acceleration of the ball is 8cm/s^2. For 3 seconds, so it accelerates at a total of 8*3 = 24 cm/s^2. Starting with a velocity of 12 cm/s, the ball would end up going 12cm/s = 24cm/s = 36cm/s.
#$&*
• Assuming that acceleration is constant, what will be its average velocity during this interval?
answer/question/discussion: ->->->->->->->->->->->-> :
Starting Velocity = 12cm/s
Ending Velocity = 36 cm/s
Average Velocity = 24 cm/s
#$&*
• How far will it travel during this interval?
answer/question/discussion: ->->->->->->->->->->->-> :
At 12 cm/s without acceleration, the ball would go 36 cm. But it is accelerating at 8 cm/s, so it would go an additional 24 cm, meaning it travels a total of 60 cm.
it's a little simpler than that
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15 minutes
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Solution
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