Phy 121
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An automobile rolls 10 meters down a constant incline with slope .05 in 8 seconds, starting from rest. The same automobile requires 5 seconds to roll the same distance down an incline with slope .10, again starting from rest.
• At what average rate is the automobile's acceleration changing with respect to the slope of the incline?
answer/question/discussion: ->->->->->->->->->->->-> :
Velocity of the first incline is 10m/8s = 1.25m/s for a slope of 0.05
Velocity of the second incline is 10m/5second = 2m/s for a slope of .1
The change in velocity is 2 – 1.25 = .75 m/s
The change in slope is .1 - .05 = .05
.75/.05 = the rate is changing at 15 m/s with respect to the incline
#$&*
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10 minutes
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You are using average velocities where you should be using changes in velocity. Right ideas, but you have to be more specific with the term 'velocity'.
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