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course Phy 121
A ball falls freely from rest at a height of 2 meters. Observations indicate that the ball reaches the ground in .64 seconds. •Based on this information what is its acceleration?
answer/question/discussion:
If the ball falls 2m in .64 seconds, its velocity will be 2/.64, or 3.12 m/s. Acceleration = change in velocity/ time = 30 m/s / .64 seconds = 46.87 m/s^2
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• Is this consistent with an observation which concludes that a ball dropped from a height of 5 meters reaches the ground in 1.05 seconds?
answer/question/discussion:
A ball dropped from 5 meters has a velocity of 5/1.05 = 4.76 m/s. Its acceleration would be 4.76/ 1.05 = 4.5 m/s^2
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• Are these observations consistent with the accepted value of the acceleration of gravity, which is 9.8 m / s^2?
answer/question/discussion:
"
This appears to be identical to your original posting, except that my notes are included in the posted version.
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