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course Phy 201
Ball Drop
You dropped a ball from a measured and/or estimated height and estimated the time required for it to drop.
Insert a copy of your data here, along with any previously submitted work you wish to include:
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Height of table form floor: 90 cm
Ramp Height Time Height dropped
4 cm 3.5 sec 90 cm
8 cm 3.5 sec 90 cm
12 cm 3.5 sec. 90 cm
16 cm 3.5 sec 90 cm
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What do you think was the percent uncertainty in the measurement of height?
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Ramp Height: 4/16*100%=25%
8/16*100%= 50%
12/16*100%= 75%
16/16*100%= 100%
Drop Height: 90/90*100%= 100%
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What do you think was the percent uncertainty in the measurement of the time of fall?
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Time of Fall:
3.5/3.5*100%= 100%
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What were the average velocity and, assuming acceleration to have been uniform, the acceleration of the falling ball?
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90-4= 86 cm/ 3.5 s= 24.6 cm/s
90-8= 82 cm/ 3.5 s= 23.4 cm/s
90-12= 78 cm/ 3.5 s= 22.8 cm/s
90-16= 74 cm/ 3.5 s= 21.1 cm/s
24.6 + 23.4+ 22.8+ 21.1= 91.9
91.9/4= 23.0 cm/s average velocity
24.6 cm/s / 3.5 s= 7.03 cm/s^2
23.4 cm/s/3.5 s= 6.7 cm/s^2
22.8 cm/s/ 3.5 s= 6.5 cm/s^2
21.1 cm/s/3.5 s= 6.03 cm/s^2
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You are dividing the average velocities by the time interval. Acceleration is obtained by dividing change in velocity by time interval.
In any case your 3.5 second interval is not a uniform-acceleration interval. See subsequent notes.
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7.03+6.7+6.5+6.03= 26.26 cm/s^2
26.26 cm/s^2/4= 6.6 cm/s^2 average acceleration
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Based on your uncertainty estimates for time of fall and height, what is the percent uncertainty in the acceleration as you observed it?
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When the ball is rolling down the ramp its acceleration is very different than when it falls to the floor.
The acceleration for your 3.5 second interval is therefore nonuniform, so your results won't be valid for the drop to the floor.
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6.03/7.03*100%= 85.8%
6.5/7.03*100%= 92.5%
6.7/7.03*100%= 95.3%
7.03/7.03*100%=100%
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This is the experiment where the ball was dropped straight to the floor.
See if you can find that data and resubmit accordingly. If not, drop some solid object to the floor from your hip. The distance of fall will be about 90 cm. Determine, as best you can, how long it takes the object to fall and use that information to complete the questions.
&#Please see my notes and, unless my notes indicate that revision is optional, submit a copy of this document with revisions and/or questions, and mark your insertions with &&&& (please mark each insertion at the beginning and at the end).
Be sure to include the entire document, including my notes.
If my notes indicate that revision is optional, use your own judgement as to whether a revision will benefit you. &#
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