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course Phy 201
Sorry I am just now getting these to you. I have been busy getting ready for quizzes. I hope that you will still accept this. I am in the process of working on the homework assignment you submitted today (10/9) that is due on Wednesday and I am hoping that I submit it tonight if not it will on Tuesday.
`q001. Light moves at 3 * 10^8 meters / second. The neutrinos beat the light by 60 nanosecondsHow far ahead of the light beam was the neutrino beam?
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3*10 ^8 m/s * 60 ns= 3.94 *10^85
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What was the percent difference in the speeds of the two beams? Calculate this based on the information provided in this question, and on the distance traveled by the two beams.
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.6%=60 nanoseconds
6.6%= 3*10^8
@& You might have a typo here.
3 * 60 is 180.
A nanosecond is 10^-9 second.
So you would get 180 * 10^-1 meters.*@
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`q002. If one swimmer moves 2% faster than another on a 500-meter race, how far ahead is the faster swimmer at the end of the race?
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500*.02= 10 meters ahead
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If the slower swimmer moves at an average speed of 1.74 m/s during the race, then what is the average speed of the faster swimmer?
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10/1.74=5.75 m/s^2
@& Presumably this means
10 m / (1.74 m/s)
which would be 5.75 seconds, not 5.75 m/s^2.
This is an important quantity, but it doesn't answer the question of average speed.*@
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What is the percent difference between the KE per kilogram of body mass, of the two swimmers?
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40.1% body difference
5.75-1.74*10= 40.1
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@& You need the two velocities to compare the KE per kilogram.
What is the definition of KE?*@