Phy 231
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A ball accelerates uniformly as it rolls 20 cm down a ramp, starting from rest, in 2 seconds.
. What are its average velocity, final velocity and acceleration?
answer/question/discussion: ->->->->->->->->->->->-> :
The average velocity is is describe by the difference in position over the change in time. So if (20-0)/(2-0)= 10 cm/s then the average velocity is 10cm/s. the instantaneous velocity is the derivative of the average velocity. So It is 20cm/s since when the time gets closer and closer to 0 it becomes 20. The acceleration is uniform so it never changes so it is just the average velocity divided by the time so it is 5cm/s2
. If the time interval is in error so that it is 3% longer than the actual time interval, then what are the actual values of the final velocity and acceleration?
answer/question/discussion: ->->->->->->->->->->->-> :
Well 3% of 2 seconds is .06 seconds then the time is actually 2.06 seconds so you take the above solution and just substitute the time with the new time
Velocity will now become 21.148 cm/s but the acceleration is 4.713 cm/s2
. What is the percent error in each?
answer/question/discussion: ->->->->->->->->->->->-> :
The percent error for the velocity is .0574% and the error for the acceleration is (5-4.713)/ 5=.0574%
. If the percent error is the same for both velocity and acceleration, explain why this must be so.
answer/question/discussion: ->->->->->->->->->->->-> :
They are the same because it was the time interval that had the error. Everything is relavent to time so if it changes the rest of it changes by the same amount.
. If the percent errors are different explain why it must be so.
answer/question/discussion: ->->->->->->->->->->->-> :
They are not different
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1 hour
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&#Very good responses. Let me know if you have questions. &#