phy 201
Your 'cq_1_02.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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you didn't include a copy of the problem; be sure to do so, because the solution doesn't make sense without it, and the posted document won't give you the information you need.
The question concerns the interval between the graph points (5 sec, 16 cm/s) to the point (13 sec, 40 cm/s) .
• What is the clock time at the midpoint of this interval?
answer/question/discussion:
9 Seconds based on the info provided that the two points are 5 seconds and 13 seconds.
• What is the velocity at the midpoint of this interval?
answer/question/discussion:
28 cm/s based on the two points given of 16cm/s and 40cm/s
• How far do you think the object travels during this interval?
answer/question/discussion:
I would say that the object travels 208 cm because if we have two given speeds of 16cm/s and 40cm/s we have an average of 26cm/s if we multiply that by the 8 seconds of the interval we get a total of 208cm.
• By how much does the clock time change during this interval?
answer/question/discussion:
8 seconds and we get this by subtracting the left most point from the right most point which is 13-5 which equals 8
• By how much does velocity change during this interval?
answer/question/discussion:
It increased 24cm/s and we get this by subtracting 16cm/s from 40cm/s
• What is the average rate of change of velocity with respect to clock time on this interval?
answer/question/discussion:
3cm/s we achieve this answer by taking our difference of distance traveled and dividing it by the difference in our time interval so 24cm/s divided by 8 seconds leaves us with 3cm/s
The units of your answer are not correct. When you divide 24 cm/s by 8 s you do not get 3 cm/s. If you divide 24 cm/s by 8 you get 3 cm/s, but you aren't dividing by 3, you are dividing by 3 s.
You have similar unit errors with the same calculation in some of your work below.
• What is the rise of the graph between these points?
answer/question/discussion:
24, we know this by taking our right most points y coordinate and subtracting our left most y coordinate from it so 40cm/s-16cm/s= 24cm/s
• What is the run of the graph between these points?
answer/question/discussion:
8, we know this by taking our right most x coordinate and subtracting our leftmost x coordinate from it which is 13s-5s=8s
• What is the slope of the graph between these points?
answer/question/discussion:
3, we get this number by taking the rise of 24 and dividing it by the run of 8 and having a final slope of 3cm/s
• What does the slope of the graph tell you about the motion of the object during this interval?
answer/question/discussion:
That with each increase in time spent the object is increasing its velocity
• What is the average rate of change of the object's velocity with respect to clock time during this interval?
answer/question/discussion:
it increased at a rate of 3cm per second between (5s, 16cm/s) and (13s, 40cm/s) we get this answer by taking the difference in distance traveled and dividing it by the amount of time spent.
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30 minutes
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Very good, except for some unit errors.
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