course MTH 174
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RESPONSE --> let u = x^3 and v' = x^2 cos(x^3) The key was recognizing that the derivative of x^3 is 3x^2 after that, it was straight forward. The substitution of w = x^3 was used in the finding of the antiderivative of v' and in the integral in the integration by parts.
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20:49:51 query problem 7.2.52 (3d edition #50) f(0)=6, f(1) = 5, f'(1) = 2; find int( x f'', x, 0, 1).
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RESPONSE --> I am having problems visualizing this one. I'll describe what I have sketched out on my paper I have a trapezoidal graph of x vs t with a point ot (0,6) and a point at (1,5) and a slope between the two. At point (1,5) the slope is 2.
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20:50:12 What is the value of the requested integral?
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RESPONSE --> I am not sure.
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20:51:04 How did you use integration by parts to obtain this result? Be specific.
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RESPONSE --> I was unable to find the result.
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20:51:11 Query Add comments on any surprises or insights you experienced as a result of this assignment.
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20:51:16 Query Add comments on any surprises or insights you experienced as a result of this assignment.
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RESPONSE -->
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