#$&*
Phy 201
Your 'cq_1_12.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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Masses of 5 kg and 6 kg are suspended from opposite sides of a light frictionless pulley and are released.
What will be the net force on the 2-mass system and what will be the magnitude and direction of its acceleration?
answer/question/discussion: ->->->->->->->->->->->-> :
The net mass traveling towards the earth would be 1 kg, so
1kg*9.8m/s^2= 9.8 newtons towards the side the 6 kg mass is suspended on.
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If you give the system a push so that at the instant of release the 5 kg object is descending at 1.8 meters / second, what will be the speed and direction of motion of the 5 kg mass 1 second later?
answer/question/discussion: ->->->->->->->->->->->-> :
The system is goin to tend to accelerate towards the side the 6kg object is suspended and the 5kg object is descendin, so I treated the 1.8m/s as negative. Since it is acceleating in the direction I am considering positive, I made the acceleration positive as well.
Vf= -1.8m/s + (9.8m/s^2)*1second= 8 m/s towards the side of the of the 6kg object.
@& Everything is right in your approach, except these masses are not in free ,so nothing acceleraties at 9.8 m/s^2.
The net force on the system is 9.8 N and the mass of the system is 11 kg. What therefore is its acceleration and what is the velocity after 1 second?*@
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During the first second, are the velocity and acceleration of the system in the same direction or in opposite directions, and does the system slow down or speed up?
answer/question/discussion: ->->->->->->->->->->->-> :
Immediately after the push, the velocity and acceleration of the system are opposite of each other. After the system reaches a velocity of 0m/s and the 5kg begins ascending, velocity and acceleration are in the same direction.
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15 minutes
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@& Very good thinking. You missed only one detail, which you should easily be able to fix.
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