#$&*
Phy 201
Your 'cq_1_15.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** **
A rubber band begins exerting a tension force when its length is 8 cm. As it is stretched to a length of 10 cm its tension increases with length, more or less steadily, until at the 10 cm length the tension is 3 Newtons.
Between the 8 cm and 10 cm length, what are the minimum and maximum tensions?
answer/question/discussion: ->->->->->->->->->->->-> :
As the length the rubberband is stretched increases, the rate at which the tension increases also increases. The maximum tension is 3 newton at length 10cm. The minimum tension is just above 0 newtons at length 8cm.
#$&*
Assuming that the tension in the rubber band is 100% conservative (which is not actually the case) what is its elastic potential energy at the 10 cm length?
answer/question/discussion: ->->->->->->->->->->->-> :
The potential energy of a 100% conservative rubberband would be 3 newtons in the opposite direction.
@& 3 Newtons is a force, not an energy.
You are right that the 3 Newton force would be in the opposite direction.*@
#$&*
If all this potential energy is transferred to the kinetic energy of an initially stationary 20 gram domino, what will be the velocity of the domino?
answer/question/discussion: ->->->->->->->->->->->-> :
(3kg*m/s^2)/0.020kg= 150m/s^2
The domino would accelerate at 150m/s^2
After 1 second the domino would be traveling at 150m/s
#$&*
If instead the rubber band is used to 'shoot' the domino straight upward, then how high will it rise?
answer/question/discussion: ->->->->->->->->->->->-> :
vf= 0m/s
Vi= 150m/s
a= -150m/s^2
150m2/s2+ 2(150m/s2)(D)
-150m2/s2=300m/s2(D)
D= .5 meters
** **
** **
@& You're not quite thinking of this in terms of energy. Check the notes at the link, and please submit a revision. so we can be sure you're on the right track here.*@
&#See any notes I might have inserted into your document, and before looking at the link below see if you can modify your solutions. If there are no notes, this does not mean that your solution is completely correct.
Then please compare your old and new solutions with the expanded discussion at the link
Solution
Self-critique your solutions, if this is necessary, according to the usual criteria. Insert any revisions, questions, etc. into a copy of this posted document. Mark any insertions with &&&& so they can be easily identified.If your solution is completely consistent with the given solution, you need do nothing further with this problem. &#