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Phy 201
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A steel ball of mass 60 grams, moving at 80 cm / sec, collides with a stationary marble of mass 20 grams. As a result of the collision the steel ball slows to 50 cm / sec and the marble speeds up to 70 cm / sec.
• Is the total momentum of the system after collision the same as the total momentum before?
answer/question/discussion: ->->->->->->->->->->->-> :
m1v1 + m2v2 = m1v1 +m2v2
60 g * 80 cm/sec + 20 g (0 cm/sec) = 60 g * 50 cm/sec + 20 g * 70 cm/sec
4800 gcm/sec = 440 gcm/sec
No the momentum of the system is not the same
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• What would the marble velocity have to be in order to exactly conserve momentum, assuming the steel ball's velocities to be accurate?
answer/question/discussion: ->->->->->->->->->->->-> :
60 g * 80 cm/sec + 20 g (0 cm/sec) = 60 g * 50 cm/sec + 20 g * v2
4800 = 3000 + 20v2
1800 = 20v2
V2 = 90
The marble would have to have a velocity of 90 cm/sec
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&#Very good responses. Let me know if you have questions. &#