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PHY 241
Your 'cq_1_02.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_02.2_labelMessages **
The problem:
A graph is constructed representing velocity vs. clock time for the interval between clock times t = 5 seconds and t = 13 seconds. The graph consists of a straight line from the point (5 sec, 16 cm/s) to the point (13 sec, 40 cm/s).
What is the clock time at the midpoint of this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
(13 + 5)/2 = 9 seconds is the clock time at the midpoint of the interval
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What is the velocity at the midpoint of this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
(16 + 40)/2 = 28 cm/s is the velocity at the midpoint of the above interval.
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How far do you think the object travels during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
The average velocity is 28 cm/s, which it maintains for (13 - 5) = 8 seconds, so I think that the object travels (28 cm/s) * (8 sec) = 224 cm during the interval.
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By how much does the clock time change during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
tf - t0 = (13 - 5) = 8 seconds
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By how much does velocity change during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
vf - v0 = (40 - 16) = 24 cm/sec
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What is the average rate of change of velocity with respect to clock time on this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
The object changed velocity from 16 cm/s to 40 cm/s, or by 24 cm/s in a period of 8 seconds, so the average rate of change of velocity with respect to clock time on this interval is 24/8 = 3 cm/sē.
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What is the rise of the graph between these points?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
Rise = 40 - 16 = 24 cm/sec
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What is the run of the graph between these points?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
Run = 13 - 5 = 8 seconds
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What is the slope of the graph between these points?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
Slope = rise/run = 24/8 = (3 cm/sec) / sec
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What does the slope of the graph tell you about the motion of the object during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
The slope gives us the average rate of change of the dependent variable with respect to the dependent variable, so in this case it would give us the average rate of change in velocity with respect to time.
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What is the average rate of change of the object's velocity with respect to clock time during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
3 cm/sē
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10 minutes
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7/10 15:45
&#Very good responses. Let me know if you have questions. &#