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Phy 201
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An automobile rolls 10 meters down a constant incline with slope .05 in 8 seconds, starting from rest. The same automobile requires 5 seconds to roll the same distance down an incline with slope .10, again starting from rest.
• At what average rate is the automobile's acceleration changing with respect to the slope of the incline?
answer/question/discussion: ->->->->->->->->->->->-> :
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I will first find the average velocity for both instances.
vAve= ‘ds/ ‘dt
vAve= 10m/8s= 1.25 m/s
vAve= 10m/5s= 2m/s
We will then find the acceleration from this. First we need to find the vf
(Slope .05) - -1.25m/s*2= 2.5m/s
(Slope .10) - - 2m/s*2= 4m/s
Then we will find the acceleration:
(Slope .05)- - (2.5-0)/8 seconds= .31m/s/s
(Slope .10)- - (4-0)/5seconds= .8m/s/s
.8-.31=.49m/s/s is the change in acceleration
The acceleration increases by .49m/s/s from the slope of .05 to .10.
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20 minutes
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Good, but there's one more step. Check the link; revision is up to you. If you're sure you understand it's not necessary; if not you should probably submit a quick revision.
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