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Phy 201
Your 'cq_1_12.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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Masses of 5 kg and 6 kg are suspended from opposite sides of a light frictionless pulley and are released.
• What will be the net force on the 2-mass system and what will be the magnitude and direction of its acceleration?
answer/question/discussion: ->->->->->->->->->->->-> :
The total weight will be 6+5= 11kg. Therefore netF= ma
The acceleration will be 9.8m/s/s because if the pulley is released it will have the acceleration of gravity. The direction is in the direction that the pulley was released and is falling.
netF= 11kg(9.8m/s/s)
netF=107.8N
by your reasoning, two equal masses suspended on opposite sides of the pulley would accelerate at 9.8 m/s^2. However this isn't the case; equal masses balance one another and will not accelerate.
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• If you give the system a push so that at the instant of release the 5 kg object is descending at 1.8 meters / second, what will be the speed and direction of motion of the 5 kg mass 1 second later?
answer/question/discussion: ->->->->->->->->->->->-> :
v0=1.8m/s
a= 9.8m/s/s because of gravity
‘dt= 1 s
We will use the formula: vf= v0+a*’dt
Vf= 1.8m/s+9.8m/s/s*1
Vf= 11.6m/s after 1 second
The motion will still be going in the direction the pulley is pushed.
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• During the first second, are the velocity and acceleration of the system in the same direction or in opposite directions, and does the system slow down or speed up?
answer/question/discussion: ->->->->->->->->->->->-> :
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The velocity and acceleration are in the same direction and the system speeds up.
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15 minutes
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Solution
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