course phy201 é€É}¡Õ¸ÛíŽÃû£v‰™|PÇ€‡ÓëÉÈôÁj¼assignment #001
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12:17:19 Explain in your own words how the standard deviation of a set of numbers is calculuated.
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RESPONSE --> the sum of the squares of the difference between the mean and each number in the set. then take the square root of that number. confidence assessment: 2
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12:21:44 Explain in your own words the process of fitting a straight line to a graph of y vs. x data, and briefly discuss the nature of the uncertainties encountered in the process. For example, you might address the question of how two different people, given the same graph, might obtain different results for the slope and the vertical intercept.
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RESPONSE --> the goal is to get the line to be as close to all the points on the graph giving you the smallest average deviation for the points. Doing this from an eyeball measurment will result in almost always different results from person to person. confidence assessment: 3
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12:24:18 Briefly state what you think velocity is and how you think it is an example of a rate.
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RESPONSE --> it is the distance something moves at a given time interval. It is a rate because it is a magnitude relative to a unit of time. confidence assessment: 3
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12:24:37 ** A rate is a change in something divided by a change in something else. This question concerns velocity, which is the rate of change of position: change in position divided by change in clock time. **
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RESPONSE --> ok self critique assessment: 3
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12:26:16 Given average speed and time interval how do you find distance moved?
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RESPONSE --> you would multiply the average speed * time to get the distance confidence assessment: 3
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12:26:25 ** You multiply average speed * time interval to find distance moved. For example, 50 miles / hour * 3 hours = 150 miles. **
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RESPONSE --> ok self critique assessment: 3
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12:27:22 Given average speed and distance moved how do you find the corresponding time interval?
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RESPONSE --> you would divide distance / average speed to get the time confidence assessment: 3
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12:27:31 ** time interval = distance / average speed. For example if we travel 100 miles at 50 mph it takes 2 hours--we divide the distance by the speed. In symbols, if `ds = vAve * `dt then `dt = `ds/vAve. Also note that (cm/s ) / s = cm/s^2, not sec, whereas cm / (cm/s) = cm * s / cm = s, as appropriate in a calculation of `dt. **
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RESPONSE --> ok self critique assessment: 3
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12:28:08 Given time interval and distance moved how do you get average speed?
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RESPONSE --> you would divide distance / time to get average speed confidence assessment: 3
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12:28:17 ** Average speed = distance / change in clock time. This is the definition of average speed. For example if we travel 300 miles in 5 hours we have been traveling at an average speed of 300 miles / 5 hours = 60 miles / hour. **
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RESPONSE --> ok self critique assessment: 3"