phy201
Your 'cq_1_02.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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A graph is constructed representing velocity vs. clock time for the interval between clock times t = 5 seconds and t = 13 seconds. The graph consists of a straight line from the point (5 sec, 16 cm/s) to the point (13 sec, 40 cm/s).
What is the clock time at the midpoint of this interval?
answer/question/discussion: 9sec
What is the velocity at the midpoint of this interval?
answer/question/discussion: 28 cm/s
How far do you think the object travels during this interval?
answer/question/discussion: 192 cm
this isn't correct; note that you should include an indication of your thinking, indicating how you found your result. In this case I expect that you multiplied the 24 cm/s change in velocity by the 8 second time interval. However `ds = vAve * `dt, not `dv * `dt.
By how much does the clock time change during this interval?
answer/question/discussion: 8 sec
By how much does velocity change during this interval?
answer/question/discussion: 24 cm/s
What is the average rate of change of velocity with respect to clock time on this interval?
answer/question/discussion: 3 cm/s/s
What is the rise of the graph between these points?
answer/question/discussion: 24
What is the run of the graph between these points?
answer/question/discussion: 8
What is the slope of the graph between these points?
answer/question/discussion: 3
rise, run and slope all have units, which should be included
units should be included with every quantity that has units
What does the slope of the graph tell you about the motion of the object during this interval?
answer/question/discussion: average rate of change of velocity with respect to time interval
What is the average rate of change of the object's velocity with respect to clock time during this interval?
answer/question/discussion: 3 cm/s/s
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15 mins
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&#Your work looks good. See my notes. Let me know if you have any questions. &#