phy201
Your 'cq_1_8.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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A ball is tossed upward with an initial velocity of 25 meters / second. Assume that the acceleration of gravity is 10 m/s^2 downward.
What will be the velocity of the ball after one second?
answer/question/discussion:
The acceleration of gravity is decreasing the upward acceleration on the ball 10m/s every second so after one second the velocity would be 15 m/s.
What will be its velocity at the end of two seconds?
answer/question/discussion:
5 m/s
During the first two seconds, what therefore is its average velocity?
answer/question/discussion:(25m/s + 5m/s) / 2s = 15m/s
How far does it therefore rise in the first two seconds?
answer/question/discussion:
Ds = vAve * Dt
Ds = 15m/s * 2s = 30 m
What will be its velocity at the end of a additional second, and at the end of one more additional second?
answer/question/discussion: -5m/s and -15m/s
At what instant does the ball reach its maximum height, and how high has it risen by that instant?
answer/question/discussion: 2.5s; this is when the acceleration reaches 0m/s and begings to fall
What is its average velocity for the first four seconds, and how high is it at the end of the fourth second?
answer/question/discussion: (-15m/s + 25m/s) / 2 = 10m/s
How high will it be at the end of the sixth second?
answer/question/discussion:
(-25m/s + 25m/s) / 2 =0m/s = vAve
right idea, but after 6 sec I believe velocity would be -35 m/s
0m/s * 6s = 0m
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20mins
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&#Your work looks good. See my notes. Let me know if you have any questions. &#